Question

我有一个数据框，其中包含玩家形式和外观作为浮动5个赛季。我的目标是移除所有参加比赛不到2个赛季的球员。

以下是数据框的示例

以下是Google云端硬盘中csv文件中数据框的链接

https://drive.google.com/file/d/1gfkPJlfoyl2sE2j8VqJYyqHJGBMXMfkO/view?usp=sharing

我想删除的球员的一个例子是Aaron Hughes，他只打了两个赛季13/14＆amp; 12/13或Abdoulaye Diaby只参加了14/15赛季。

我想保留的球员的一个例子是至少打了4个赛季的Abdoulaye Keita。

我的预期输出是：

Players club    16/17   15/16   14/15   13/14   12/13   17/18
    Form    Apps    Form    Apps    Form    Apps    Form    Apps    Form    Apps    Form    Apps
    0   Aaron Cresswell West Ham United 2.269231    26.0    3.108108    37.0    2.921053    38.0    0.000000    0.0 0.000000    0.0 2.400000    30.0
    1   Aaron Hunt  Hamburger SV    2.590909    22.0    2.136364    22.0    1.800000    15.0    3.741935    31.0    4.035714    28.0    2.500000    24.0
    2   Aaron Lennon    Everton 1.818182    11.0    2.760000    25.0    2.217391    23.0    2.555556    27.0    3.147059    34.0    1.913043    23.0
    3   Aaron Ramsey    Arsenal 2.173913    23.0    3.096774    31.0    3.241379    29.0    4.956522    23.0    1.833333    36.0    4.300000    20.0
    4   Abdoul Camara   En Avant de Guingamp    0.000000    0.0 2.235294    17.0    0.000000    0.0 1.500000    10.0    1.666667    15.0    0.000000    0.0
    5   Abdoulaye Doucoure  Watford 1.750000    20.0    4.558333    31.0    2.600000    35.0    3.750000    20.0    3.250000    4.0 3.000000    32.0
    6   Abdoulaye Keita Le Havre AC 1.571429    21.0    1.000000    4.0 2.000000    5.0 1.200000    5.0 0.000000    0.0 0.00

任何帮助将不胜感激！感谢

Answer 1

**Here is a better solution to your question.**

df['count'] = 0
df.loc[df['16/17']['Apps']>9.0, 'count'] += 1
df.loc[df['15/16']['Apps']>9.0, 'count'] += 1
df.loc[df['14/15']['Apps']>9.0, 'count'] += 1
df.loc[df['13/14']['Apps']>9.0, 'count'] += 1
df.loc[df['12/13']['Apps']>9.0, 'count'] += 1

df[df['count']>3]

Answer 2

x = 0
i = 0
array = []

while i < len(df):
    if df['16/17']['Apps'][i] > 9.0:
        x += 1
    elif df['15/16']['Apps'][i] > 9.0:
        x += 1
    elif df['14/15']['Apps'][i] > 9.0:
        x += 1
    elif df['13/14']['Apps'][i] > 9.0:
        x += 1
    elif df['12/13']['Apps'][i] > 9.0:
        x += 1
    if x > 2:
        array.append(True)
        x = 0
    else:
        array.append(False)
        x = 0

df[array]

查找具有3个或更多列满足条件Pandas的所有行

2 个答案: