Question

我有2张桌子。第一个包含组列表。第二个包含发布帖子的时间。您需要获取一个组列表，并发布给他们，但帖子应按时间排序。当我进行分组时，禁食时间不一样。

            table time_post
+----+---------------+--------+-----------+
| id |  id_public    | img_id | time_post |
+----+---------------+--------+-----------+
|  1 |             1 |      2 |         5 |
|  2 |             2 |      1 |         1 |
|  7 |             1 |      1 |        55 |
|  8 |             1 |      3 |         2 |
| 10 |             3 |      3 |         4 |
| 11 |             3 |      3 |         2 |
+----+---------------+--------+-----------+

     table public
+----+-----------+-------------+--------------+-----------+
| id | id_public | time_update | access_token | text_send |
+----+-----------+-------------+--------------+-----------+
|  1 |      9876 |           0 | 1234         |           |
|  2 |     12345 |           0 | 12345        |           |
|  3 |     22222 |           0 |              |           |
+----+-----------+-------------+--------------+-----------+
                 To get this result
+-----------+-------------+--------------+-----------+
| id_public | time_post   | access_token | text_send |
+-----------+-------------+--------------+-----------+
|      9876 |           2 | 1234         |           |
|     12345 |           1 | 12345        |           |
|     22222 |           2 |              |           |
+-----------+-------------+--------------+-----------+

time_post应按最小值

排序

Answer 1

window

<强>输出

// worker.js
function foo() {
  console.log("hello worker");
}

self['foo']()

<强>演示

http://sqlfiddle.com/#!9/fbb18/6

Answer 2

SELECT p.id_public，min（t.time_post），p.access_token，p.text_send FROM public as p，time_post as t 在哪里p.id = t.id_public p.id_public小组，p.access_token，p.text_send

试试这个，我希望它有效。

对于演示链接， https://www.db-fiddle.com/f/46M8v9opAeVc834tZ15Vur/0#&togetherjs=nRGqfr7bdE

sql请求GROUP BY

2 个答案: