Question

我有一个显示0的计数器，我想在它变为0时隐藏它。因此，如果计数器显示（0天6小时25分钟）我希望它（6小时25分钟），只需将其隐藏在0 ... 这是我的代码：

<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}
</style>
</head>
<body>

<p id="demo"></p>

<script>
// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);
</script>

</body>
</html>

感谢您的帮助

Answer 1

您可以查看days === 0时间并将其填空

days = days === 0 ? '' : days + "d "

// Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = days + hours + "h "
    + minutes + "m " + seconds + "s ";

相同的小时和分钟

Answer 2

如果天== 0

，您可以使用三元运算符chceck

document.getElementById("demo").innerHTML = ((days) ? days + "d " : '') + hours + "h " + minutes + "m " + seconds + "s ";

<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style>
p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}
</style>
</head>
<body>

<p id="demo"></p>

<script>
// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = ((days) ? days + "d " : '') + hours + "h "
    + minutes + "m " + seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);
</script>

</body>
</html>

Answer 3

如果您想对所有输出执行此操作并将1d 0h 52m 0s显示为1d 52m，则逻辑应为：

// Output the result in an element with id="demo"
document.getElementById("demo").innerHTML = 
                         ((!days) ? '' : days + "d ") + 
                         ((!days && !hours) ? '' : hours + "h ") +
                         ((!days && !hours && !minutes) ? '' : minutes + "m ") + 
                         ((!days && !hours && !minutes && !seconds) ? '' : seconds + "s ";

这样的时间就像0d 0h 52m 0s

一样呈现52m 0s

Answer 4

您可以通过document.getElementById("demo").innerHTML更改时间来设置条件，

(days === 0 ? '' : days + "d ") +
(hours === 0 ? '' : hours + "h ")+
(minutes === 0 ? '' : minutes + "m ")+ 
 seconds + "s ";

这将检查days，hours和minutes的零值，并在HTML中指定null，

// Set the date we're counting down to
var countDownDate = new Date("April 12, 2018 15:37:25").getTime();
// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();
    
    // Find the distance between now an the count down date
    var distance = countDownDate - now;
    
    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);
    
    // Output the result in an element with id="demo"
    document.getElementById("demo").innerHTML = 
    (days === 0 ? '' : days + "d ") +
    (hours === 0 ? '' : hours + "h ")+
    (minutes === 0 ? '' : minutes + "m ")+ 
     seconds + "s ";
    
    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        document.getElementById("demo").innerHTML = "EXPIRED";
    }
}, 1000);

p {
  text-align: center;
  font-size: 60px;
  margin-top:0px;
}

<p id="demo"></p>

当它变为零时我怎么能隐藏计数器日？

4 个答案: