Question

程序在达到player[aplyr].grid[X][Y] = isSHIP;

时崩溃

const char isSHIP = 'S';

struct PLAYER{

char grid[10][10];

}player[3]; //player 1 and 2. Ignore player 0


int main ()
{
    int X;
    int Y;
    //"PLACE SHIPS" phase of game
    //Loop through each player... 
    for (int aplyr=1; aplyr<3; ++aplyr)
    {
        //Loop through each ship type to place
        for (int thisShip=0; thisShip<15; ++thisShip)
        {       

         //Get input from user
            PlaceShips();

         //Add the FIRST grid point to the current player's game board
            player[aplyr].grid[X][Y] = isSHIP;

        }


            //Loop back until 15 points have been placed
    }
        //Loop back through each player
}

void PlaceShips()
{
    int x, y, player;
    bool goodInput = false;
    do {
         //get X pick
        cout << "Enter X and Y coordinates:  ";
        cin >> x >> y;
        if (x >= 10 && y>=10)
        {
            goodInput = false;
            cin.clear();
            cout << "Out of Range!";
            break;
        }
        else
        {
            goodInput = true;
        }

    } while (!goodInput);  
}

Answer 1

在main函数中，您创建变量X和Y而不初始化它们的值。这意味着它们可以包含任何值，并且很可能超出网格范围。这将导致程序在指定的行崩溃。

程序在到达线路时崩溃

1 个答案: