Question

通常我在App.xaml，ContentPage.xaml或View.xaml级别内定义datatemplate。是否可以在单独的xaml文件中定义datatemplate，以便我可以为代码中的视图分配datatemplate

if (Device.Idiom == TargetIdiom.Phone)
                childListView.ItemTemplate = (DataTemplate)Resources["phoneSignInTemplate"];
            else if (Device.Idiom == TargetIdiom.Tablet)
                childListView.ItemTemplate = (DataTemplate)Resources["tabletSignInTemplate"];

如果我在App.xaml或ContentPage或Views级别放置太多datatemplate。我担心它会在加载页面时影响性能。

Answer 1

您可以在xaml中生成新的ViewCell并将它们用作DataTemplates：

MyTextViewCell.xaml：

<?xml version="1.0" encoding="UTF-8"?>
<ViewCell 
    xmlns="http://xamarin.com/schemas/2014/forms" 
    xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
    x:Class="XFTests.MyTextViewCell">
    <ViewCell.View>
        <StackLayout>
            <Label
                Text="Not a phone" />
            <Label Text="{Binding .}" />
        </StackLayout>
    </ViewCell.View>
</ViewCell>

MyTextViewCellPhone.xaml：

<?xml version="1.0" encoding="UTF-8"?>
<ViewCell 
    xmlns="http://xamarin.com/schemas/2014/forms" 
    xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
    x:Class="XFTests.MyTextViewCellPhone">
    <ViewCell.View>
        <StackLayout>
            <Label
                Text="Phone" />
            <Label Text="{Binding .}" />
        </StackLayout>
    </ViewCell.View>
</ViewCell>

然后将您需要的那个分配给项目模板。

ListView listView = new ListView
{
    ItemsSource = new string[] { "Max", "John" }
};

if (Device.Idiom == TargetIdiom.Phone)
    listView.ItemTemplate = new DataTemplate(typeof(MyTextViewCellPhone));
else
     listView.ItemTemplate = new DataTemplate(typeof(MyTextViewCell));

Xamarin表单：我们可以使用Views或App.xaml或Content Page分隔datatemplate

1 个答案: