MSSQL - GROUP_CONCAT

时间:2018-04-11 20:31:06

标签: sql sql-server string-aggregation

以下是示例数据:

IdProduit   Localisation    Qte_EnMain
4266864286880063006 E2-R40-B-T  13.00000
4266864286880063006 E2-R45-B-T  81.00000
4266864286880063007 E2-R45-C-T  17.00000
4266864286880063008 E2-R37-B-T  8.00000

这就是我想要的

IdProduit           AllLocalisation
4266864286880063006 E2-R40-B-T (13), E2-R45-B-T (81)
4266864286880063007 E2-R45-C-T (17)
4266864286880063008 E2-R37-B-T (8)

我在论坛上看了所有GROUP_CONCAT的例子,我尝试了几次测试。

我真的不懂STUFF()。

以下是我想做的事情:

SELECT
  a.IdProduit,
  GROUP_CONCAT(
      CONCAT(b.Localisation, ' (', CAST(ROUND(a.Qte_EnMain, 0) AS NUMERIC(36, 0)), ')')
  ) AS AllLocation
FROM
  ogasys.INV_InventENTLoc a
  LEFT JOIN ogasys.INV_LocName b ON a.IdLoc = b.IdLoc
GROUP BY a.IdProduit, b.Localisation, a.Qte_EnMain

现在因为GROUP_CONCAT没有使用MSSQL,这是我在这个论坛上用所有例子创建的查询。

SELECT
  DISTINCT
  a1.IdProduit,
  STUFF((SELECT DISTINCT '' + b2.Localisation
         FROM
           ogasys.INV_InventENTLoc a2
           LEFT JOIN ogasys.INV_LocName b2 ON a2.IdLoc = b2.IdLoc
         WHERE a2.IdLoc = a1.IdLoc
         FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 0, '') data
FROM
  ogasys.INV_InventENTLoc a1
  LEFT JOIN ogasys.INV_LocName b1 ON a1.IdLoc = b1.IdLoc
ORDER BY a1.IdProduit

查询只按行返回一个本地化我不明白如何使这个查询有效。

修改

这是我的情况的解决方案:

SELECT
  a.IdProduit,
  STUFF(
      (SELECT ', ' + b2.Localisation + ' (' + CAST(CAST(ROUND(a2.Qte_EnMain, 0) AS NUMERIC(36, 0)) AS VARCHAR(32)) + ')'
       FROM ogasys.INV_InventENTLoc a2
         LEFT JOIN ogasys.INV_LocName b2 ON a2.IdLoc = b2.IdLoc
       WHERE a.IdProduit = a2.IdProduit
       FOR XML PATH (''))
      , 1, 1, '') AS AllLocalisation
FROM
  ogasys.INV_InventENTLoc a
  LEFT JOIN ogasys.INV_LocName b ON a.IdLoc = b.IdLoc
GROUP BY a.IdProduit

1 个答案:

答案 0 :(得分:0)

使用STUFF

declare @table table (IdProduit varchar(100), Localisation varchar(50),  Qte_EnMain float)

insert into @table
values 
('4266864286880063006','E2-R40-B-T',  13.00000),
('4266864286880063006','E2-R45-B-T',  81.00000),
('4266864286880063007','E2-R45-C-T',  17.00000),
('4266864286880063008','E2-R37-B-T',  8.00000)


select IdProduit,
  STUFF (
        (SELECT   
                ',' + localisation + concat(' (',cast(qte_enMain as varchar(4)),') ')
        FROM @table t2
        where t2.IdProduit = t1.IdProduit
        FOR XML PATH('')), 1, 1, ''
    )
 from @table t1
group by
IdProduit