Question

我有一个基于交易日期的派生临时表，如下所示：

-----------------------------------------------------------------------------------
|Account_No| Customer_Name   | Invoice_No  | Amount | Reason_Comment | Trans_Code |
-----------------------------------------------------------------------------------
|12345678  | John Doe        | A23782998   | 326.28 | Payment        |          2 |
-----------------------------------------------------------------------------------
|12345678  | John Doe        | A23782998   | 173.72 | Adjustment     |          3 |
-----------------------------------------------------------------------------------
|12345678  | John Doe        | A23782998   |   0.00 | Paid In Full   |  X         |
-----------------------------------------------------------------------------------
|23456789  | Bob Marley      | B58787934   | 500.00 | Payment        |          2 |
-----------------------------------------------------------------------------------
|23456789  | Bob Marley      | B58787934   |   0.00 | Paid In Full   |  X         |
-----------------------------------------------------------------------------------
|89034537  | Eric Clapton    | C78236428   |   0.00 | Paid In Full   |  X         |
-----------------------------------------------------------------------------------

正如您可能注意到的那样，Bob Markey付款并且他的帐户显示为“已付款” Eric Clapton很顺利。他提前支付了款项，因此已经显示为“全额支付” John Doe在这里需要一点'调整'的帮助，以便我们可以将他的账户余额归零，从而'全额支付'

付款交易的Trans_Code为2，调整3和全额付款为X.

我想排除在TransCode中只有“已付费”原因或X的交易。

我试过了：

SELECT * 
FROM #temp_table 
WHERE Account_No NOT IN 
     (SELECT Account_No FROM #temp_table 
      WHERE Reason_Comment = 'Paid In FUll'
        AND Reason_Comment <> 'PAYMENT' 
        AND Reason_Comment <> 'ADJUSTMENT')

也许，我应该使用NOT EXISTS

修改
这是我正在使用的表格。由于我指定了日期范围，因此某些帐户只有一行，即“已付款”行，因为调整或付款发生在指定的日期范围之前。例如，下表中的最后一行（Johnson Doe）。我想排除最后一行。

----------------------------------------------------------------------------------------------------------
|Account_No| Customer_Name   | Invoice_No  | Amount | Trans_No  |Reason_Comment | Trans_Date | Trans_Code|
----------------------------------------------------------------------------------------------------------
|12345678  | John Doe        | A23782998   | 326.28 |1234567    |Payment         | 2018-04-01 |         2|
----------------------------------------------------------------------------------------------------------
|12345678  | John Doe        | A23782998   | 687.58 |           |Amount Due      |            |         4|
----------------------------------------------------------------------------------------------------------
|23456789  | Jane Doe        | B12378299   | 123.56 |2345678    |Payment         | 2018-04-02 |         2|
----------------------------------------------------------------------------------------------------------
|23456789  | Jane Doe        | B12378299   | 336.44 |3456789    |Adjustment      | 2018-04-03 |         3|
----------------------------------------------------------------------------------------------------------
|23456789  | Jane Doe        | B12378299   |        |           |Paid In Full    |            |         X|
----------------------------------------------------------------------------------------------------------
|34567890  | Jonas Doe       | C34567998   | 500.55 |4567891    |Payment         | 2018-04-06 |         2|
----------------------------------------------------------------------------------------------------------
|34567890  | Jonas Doe       | C34567998   |        |           |Paid In Full    |            |         X|
----------------------------------------------------------------------------------------------------------
|45678912  | Johnson Doe     | D45678756   |        |           |Paid In Full    |            |         X|
----------------------------------------------------------------------------------------------------------

Answer 1

您可以使用：

SELECT *
FROM tab t
WHERE NOT EXISTS (SELECT 1
                  FROM tab t2
                  WHERE t.Account_no = t2.Account_no
                    AND t.Invoice_no = t2.Invoice_no
                    AND (Reason_Comment IN ('Paid In FUll')
                         OR TransCode = 'X')
                  );

Answer 2

- 您可以用不同的方式编写查询

  ON DUPLICATE KEY UPDATE portfolioValue = VALUES(portfolioValue)

Answer 3

正如我在评论中所述，您的帖子并不清楚您究竟需要排除什么，但从您提供的示例和查询中，我得出结论，您需要排除没有的客户任何调整或分期付款计划（人们喜欢你的例子中的Eric Clapton），因为你需要跟踪已经全额支付的付款（提前或早于到期付款），你不应该跟进分期付款或调整以确保您获得全额付款？这就是我理解你的问题的方式，这对我来说是有意义的（也许）。

如果您正在寻找什么，那么您可以这样做：

更新（使用新提供的示例）

SELECT
    Account_No, 
    Customer_Name, 
    Invoice_No, 
    Amount, 
    Trans_No,
    Reason_Comment, 
    Trans_Date,
    Trans_Code 
FROM(
SELECT
    Account_No, 
    Customer_Name, 
    Invoice_No, 
    Amount, 
    Trans_No,
    Reason_Comment, 
    Trans_Code, 
    CASE 
        WHEN 
            COUNT(Account_No) OVER(PARTITION BY Account_No) = 1 AND Trans_Code = 'X'            
            THEN NULL 
        ELSE  
           COUNT(Account_No) OVER(PARTITION BY Account_No)
    END  AS NumberOfPayments, 
    Trans_Date 
FROM Trans
) D
WHERE 
    NumberOfPayments IS NOT NULL 
AND (
        CAST(Trans_Date AS DATE) >= '2018-04-01'
    AND CAST(Trans_Date AS DATE) <= '2018-04-06'
    OR  Trans_Date IS NULL 
)

这将返回：

| Account_No | Customer_Name | Invoice_No | Amount | Trans_No | Reason_Comment |           Trans_Date | Trans_Code |
|------------|---------------|------------|--------|----------|----------------|----------------------|------------|
|   12345678 |      John Doe |  A23782998 | 326.28 |  1234567 |        Payment | 2018-04-01T00:00:00Z |         2  |
|   12345678 |      John Doe |  A23782998 | 687.58 |   (null) |     Amount Due |               (null) |         4  |
|   23456789 |      Jane Doe |  B12378299 | 123.56 |  2345678 |        Payment | 2018-04-02T00:00:00Z |         2  |
|   23456789 |      Jane Doe |  B12378299 | 336.44 |  3456789 |     Adjustment | 2018-04-03T00:00:00Z |         3  |
|   23456789 |      Jane Doe |  B12378299 | (null) |   (null) |   Paid In Full |               (null) |         X  |
|   34567890 |     Jonas Doe |  C34567998 | 500.55 |  4567891 |        Payment | 2018-04-06T00:00:00Z |         2  |
|   34567890 |     Jonas Doe |  C34567998 | (null) |   (null) |   Paid In Full |               (null) |         X  |

NumberOfPayments 将根据发票号计算每个帐号的付款。您可以根据需要更改CASE规则，还可以添加对分期付款有用的付款订单（付款1，付款2，付款3 ..等）。您只需添加以下行：

ROW_NUMBER() OVER(PARTITION BY Invoice_No ORDER BY Trans_Code) AS PaymnetNumber

这是Fiddle Demo

SQL Server 2014 - 如何排除没有特定值的记录？

3 个答案: