Question

我有一个数组objArray。我想创建一个函数，以便检查是否有另一个具有相同name键的对象。如果存在，则会在qty键中添加+1。如果该对象不存在，它会将新对象推送到数组。

var objArray = [
  {"name":"bike","color":"blue","qty":2},
  {"name":"boat","color":"pink", "qty":1},
];

var carObj = {"name":"car","color":"red","qty":1};
var bikeObj = {"name":"bike","color":"blue","qty":1};
  
function checkAndAdd (obj) {
    for (var i = 0; i < objArray.length; i++) {
      if (objArray[i].name === obj.name) {
          objArray[i].qty++;
          break;
      }
      else {
          objArray.push(obj);
      }
    };
}

checkAndAdd(carObj);

console.log(objArray);

checkAndAdd(bikeObj);

console.log(objArray);

checkAndAdd(carObj);之后

console.log(objArray);

应该给予

[
  {"name":"car","color":"red", "qty":1},
  {"name":"bike","color":"blue","qty":2},
  {"name":"boat","color":"pink", "qty":1},
]

fter checkAndAdd(bikeObj);

console.log(objArray);

应该给予

[
  {"name":"car","color":"red", "qty":1},
  {"name":"bike","color":"blue","qty":3},
  {"name":"boat","color":"pink", "qty":1},
]

提前致谢！

Answer 1

如果找到一个增加数量的项目，则需要检查所有对象并退出该功能。

如果没有找到推动物体。

＆＃13;

var objArray = [{ name: "bike", color: "blue", qty: 2 }, { name: "boat", color: "pink", qty: 1 }],
    carObj = { name: "car", color: "red", qty: 1 },
    bikeObj = { name: "bike", color: "blue", qty: 1 };
  
function checkAndAdd (obj) {
    for (var i = 0; i < objArray.length; i++) {
        if (objArray[i].name === obj.name) {
            objArray[i].qty++;
            return;                             // exit loop and function
        }
    }
    objArray.push(obj);
}

checkAndAdd(carObj);
console.log(objArray);

checkAndAdd(bikeObj);
console.log(objArray);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

您还可以使用find搜索对象属性。

在推送对象之前使用Object.assign将克隆对象，并且在更改qty时不会更改原始对象（如果添加更多具有相同名称的对象。）

var objArray = [
    {"name":"bike","color":"blue","qty":2},
    {"name":"boat","color":"pink", "qty":1},
];

var carObj = {"name":"car","color":"red","qty":1};
var bikeObj = {"name":"bike","color":"blue","qty":1};

function checkAndAdd(obj) {
  let o = objArray.find(o => o.name === obj.name);  //Find if name exist

  if (!o) objArray.push(Object.assign({},obj));     //If not exist, push. 
  else o.qty += obj.qty;                            //If exist, add the qty
}

checkAndAdd(carObj);
console.log(objArray);

checkAndAdd(bikeObj);
console.log(objArray);

Answer 3

使用findIndex在objArray中查找对象是否存在。如果存在，则更新对象，否则推送新对象

var objArray = [{
    "name": "bike",
    "color": "blue",
    "qty": 2
  },
  {
    "name": "boat",
    "color": "pink",
    "qty": 1
  },
];

var carObj = {
  "name": "car",
  "color": "red",
  "qty": 1
};
var bikeObj = {
  "name": "bike",
  "color": "blue",
  "qty": 1
};

function checkAndAdd(obj) {
  var x = objArray.findIndex(function(item) {
    return item.name === obj.name;

  });
  if (x === -1) {
    objArray.push(obj)
  } else {
    objArray[x].qty = objArray[x].qty + obj.qty
  }
}

checkAndAdd(carObj);
checkAndAdd(bikeObj);
console.log(objArray);

Answer 4

问题是你在循环中else，而不是在找到后立即返回，只在循环外调用push()。

更清洁的方法是：

push()

Answer 5

足够简单：

function checkAndAdd(obj) {
for (var i=0; i < objArray.length; i++) {
    if (objArray[i]name === obj.name) {
        objArray[i].qty++;
        return
    }
}
objArray.push(obj)
}

说明：

每次对象名称不匹配时，您的功能都在推送。相反，当此函数匹配名称时，它会增加qty并停止，然后如果循环结束而没有任何匹配，则会推送obj。

Javascript - 检查对象数组中是否存在对象并更新数量

5 个答案:

说明：