Question

var http = require('http');
var express = require('express');
var app = express();
var server = require('http').Server(app);
var io = require('socket.io').listen(server);
var path = require('path');
var mysql = require('mysql');
var bodyParser = require('body-parser');
var jsonParser = bodyParser.json({type: 'application/json'});
var cookieParser = require('cookie-parser');
var cors = require('cors');
app.use('*', cors());
app.set('views', path.join(__dirname, 'views'));
app.use(express.static(path.join(__dirname, 'public')));
// parse application/x-www-form-urlencoded
app.use(bodyParser.urlencoded({ extended: false }))

// parse application/json
app.use(bodyParser.json({type: 'application/json'}));
app.use(cookieParser());

这是我使用jquery API的客户端代码

$.ajax({
        url: "/checkIfAdmin",
        type: 'GET',
        data: JSON.stringify({'password': 'password', 'username': 'username'}),
        crossDomain: true,
        async: true,
        cache: false,
        contentType: "application/json; charset=utf-8",
        processData: false,
        success: function (data) {
               // doing something
        },
        error: function(data){
             // throw error here!
        }
});

身体解析器一直在返回一个空的身体，现在正试图解决这个问题一段时间，在下面的应用程序路线上

app.get('/checkIfAdmin', jsonParser, function(req, res){
     console.log(req.body);
     // Am getting an empty object ie {}
});

得到{}（空对象）请问我该如何解决这个问题

Answer 1

它获得了API。因此，您将获得req.query中的数据。

如何阻止body-parser在nodejs应用程序中返回undefined

1 个答案: