在运行下面的NetworkX python 3.5代码(在Jupyter中)时,我收到一个我不太懂的错误。 任何帮助是极大的赞赏。
import pandas as pd
import networkx as nx
import numpy as np
import matplotlib.pyplot as plt
import os, warnings
warnings.filterwarnings('ignore')
%matplotlib inline
%config InlineBackend.figure_format = 'retina'
## NODES
a = [ ( 'a_%d' % i, {'a' : i}) for i in range(0,5) ]
b = [ ( 'b_%d' % i, {'b' : i}) for i in range(0,5) ]
c = [ ( 'c_%d' % i, {'c' : i}) for i in range(0,5) ]
d = [ ( 'd_%d' % i, {'d' : i}) for i in range(0,5) ]
E = [ ( 'E_%d' % h, {'a': i}, {'b': j}, {'c': k}, {'d': l} )
for h in range(1,626) for i in range(0,5)
for j in range(0,5) for k in range(0,5)
for l in range(0,5) ]
## GRAPH initialization
testgraph = nx.Graph()
list_of_nodegroups = [a, b, c , d, E]
这就是它失败的地方:
## GRAPH construction - adding nodes
for ng1 in list_of_nodegroups1:
testgraph.add_nodes_from(ng1)
我收到此错误:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
/usr/local/lib/python3.5/dist-packages/networkx/classes/graph.py in add_nodes_from(self, nodes_for_adding, **attr)
535 try:
--> 536 if n not in self._node:
537 self._adj[n] = self.adjlist_inner_dict_factory()
TypeError: unhashable type: 'dict'
During handling of the above exception, another exception occurred:
ValueError Traceback (most recent call last)
<ipython-input-10-718f064c86a3> in <module>()
1 for ng1 in list_of_nodegroups:
----> 2 testgraph.add_nodes_from(ng1)
/usr/local/lib/python3.5/dist-packages/networkx/classes/graph.py in add_nodes_from(self, nodes_for_adding, **attr)
540 self._node[n].update(attr)
541 except TypeError:
--> 542 nn, ndict = n
543 if nn not in self._node:
544 self._adj[nn] = self.adjlist_inner_dict_factory()
ValueError: too many values to unpack (expected 2)
参考(据我所知)2件事:
我正在试图弄清楚如何在这段代码或其他地方解决这个问题,并且非常感谢任何帮助!
编辑:
我的目标是制作一个由4种类型的儿童节点组成的图表&#39;是a,b,c,d和1种类型的母节点&#39;是E,像这样:
[ ('E1', {'a0': 0, 'b0': 0, 'c0': 0, 'd0': 0} ),
('E2', {'a1': 1, 'b0': 0, 'c0': 0, 'd0': 0} ),
('E3', {'a1': 1, 'b1': 1, 'c0': 0, 'd0': 0} ),
...
('E625', {'a5': 5, 'b5': 5, 'c5': 5, 'd5': 5} ),
]
答案 0 :(得分:1)
Documentation for Graph.add_nodes_from(nodes_for_adding, **attr)
:nodes_for_adding
(可迭代容器) - 节点容器(列表,字典,集等)。或(节点,属性字典)元组的容器。使用属性dict更新节点属性。
列表E
中的每个元素都是一个包含一个节点和4个dicts的元组,而add_nodes_from
只接受一个dict。这4个dicts应该合并为一个单词:{'a': i, 'b': j, 'c': k, 'd': l}
。
此外,列表E
有625×5⁴= 390625个元素。这是你的意图,还是你试图枚举节点?如果要枚举,则无法按预期工作。相反,使用
from itertools import product
E = [('E_%d' % h, {'a': i, 'b': j, 'c': k, 'd': l})
for h, (i, j, k, l) in enumerate(product(range(5), repeat=4), start=1)]