Question

我已在我的应用程序中做出反应Dnd（拖放）。我想为此进行e2e测试。

我想要模拟的是拖动特定数据并放到特定位置。我如何启用此功能？

我拥有的是：

test.js

const mouse = page.mouse;
await mouse.down();
await mouse.move(126, 19);
await page.waitFor(400);

使用此代码选择已完成。但拖动不起作用。我该如何实现呢？

Answer 1

以下方法将允许您在Puppeteer中模拟拖放动作：

const example      = await page.$( '#example' );
const bounding_box = await example.boundingBox();

await page.mouse.move( bounding_box.x + bounding_box.width / 2, bounding_box.y + bounding_box.height / 2 );
await page.mouse.down();
await page.mouse.move( 126, 19 );
await page.mouse.up();

Answer 2

这是我用来拖放木偶的片段：

//This assumes only one element will be found for selectors you provide, otherwise there's ambiguity on which element was selected.
//In my code I'm throwing on more than 1 element found

async dragAndDrop(page, originSelector, destinationSelector) {
  await page.waitFor(originSelector)
  await page.waitFor(destinationSelector)
  const origin = await page.$(originSelector)
  const destination = await page.$(destinationSelector)
  const ob = await origin.boundingBox()
  const db = await destination.boundingBox()

  console.log(`Dragging from ${ob.x + ob.width / 2}, ${ob.y + ob.height / 2}`)
  await page.mouse.move(ob.x + ob.width / 2, ob.y + ob.height / 2)
  await page.mouse.down()
  console.log(`Dropping at   ${db.x + db.width / 2}, ${db.y + db.height / 2}`)
  await page.mouse.move(db.x + db.width / 2, db.y + db.height / 2)
  await page.mouse.up()
}

请注意，not fully仍支持对操纵up的拖放操作。

Answer 3

Puppeteer的任何特定解决方案都不适合我，因此我最终将本机javascript写入文件并将其导入Puppeteer（在我的情况下为Jest）。

drag-and-drop.js

async function dragAndDrop(source, target) {
  await page.evaluate((source, target) => {
    source = document.querySelector('#'+source);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("mousedown", true, true, null);
    event.clientX = source.getBoundingClientRect().top;
    event.clientY = source.getBoundingClientRect().left;
    source.dispatchEvent(event);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("dragstart", true, true, null);
    event.clientX = source.getBoundingClientRect().top;
    event.clientY = source.getBoundingClientRect().left;
    source.dispatchEvent(event);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("drag", true, true, null);
    event.clientX = source.getBoundingClientRect().top;
    event.clientY = source.getBoundingClientRect().left;
    source.dispatchEvent(event);


    target = document.querySelector('#'+target);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("dragover", true, true, null);
    event.clientX = target.getBoundingClientRect().top;
    event.clientY = target.getBoundingClientRect().left;
    target.dispatchEvent(event);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("drop", true, true, null);
    event.clientX = target.getBoundingClientRect().top;
    event.clientY = target.getBoundingClientRect().left;
    target.dispatchEvent(event);

    event = document.createEvent("CustomEvent");
    event.initCustomEvent("dragend", true, true, null);
    event.clientX = target.getBoundingClientRect().top;
    event.clientY = target.getBoundingClientRect().left;
    target.dispatchEvent(event);
  }, source, target);
}

test.js

const dragAndDrop = require('./drag-and-drop')

describe('when dragging and dropping todo', () => {

  it('should change order on DOM', async () => {
    const firstTodo = await page.evaluate(() => document.querySelectorAll('.input-container .input')[0].id);
    const secondTodo = await page.evaluate(() => document.querySelectorAll('.input-container .input')[1].id);

    dragAndDrop(firstTodo, secondTodo);

    const newFirstTodo = await page.evaluate(() => document.querySelectorAll('.input-container .input')[0].id);
    const newSecondTodo = await page.evaluate(() => document.querySelectorAll('.input-container .input')[1].id);

    expect(newFirstTodo).toEqual(secondTodo)
    expect(newSecondTodo).toEqual(firstTodo)
  });
});

比内置的Puppeteer功能要多得多的工作，但希望对于其他需要更多控制拖放的人来说，这是一个简单易行的复制和粘贴解决方案。

如何模拟木偶戏中的拖放动作？

3 个答案: