首先查询选定的机构,其次是获得该机构的最新评论。
首先查询:
SELECT
instituteId,
instituteName,
description
FROM institutions
WHERE instituteId IN ('1','2','3')";
第二次查询:
SELECT
name,
review,
timestamp
FROM reviews
WHERE instituteId='1'
ORDER BY timestamp DESC
LIMIT 1;
答案 0 :(得分:1)
SELECT i.instituteId,
i.instituteName,
i.description ,
r.name,
r.review,
r.timestamp
FROM institutions i
INNER JOIN review r
ON i.instituteid = r.instituteId
INNER JOIN (SELECT instituteId,
MAX(timestamp) as timestamp
FROM reviews
GROUP BY instituteId
) r1
ON r.instituteid = r1.instituteId
AND r.timestamp = r1.timestamp
WHERE instituteId IN ('1','2','3')
答案 1 :(得分:1)
有很多方法可以做到这一点。但是下面这个给了我在大型数据集中的最佳性能。是的,不要忘记索引列。
//this is just a pseudocode
//df is a master data frame
df1 = df.select(some columns)
df2 = df.select(some columns)
df3 = df.select(some columns)
df4 = df.select(some columns)
df1.write(dir1)
df2.write(dir2)
df3.write(dir3)
df4.write(dir4)
答案 2 :(得分:0)
select i.instituteId, i.instituteName, i.description,
r.name,r.review, r.timestamp
from institutions i inner join reviews r on i.instituteId=r.instituteId
WHERE instituteId IN ('1','2','3')
ORDER BY timestamp DESC LIMIT 1
答案 3 :(得分:0)
您可以在一个点上连接两个表,这两个表匹配相同的值和属性
语法: SELECT column_name(s)FROM table1 INNER JOIN table2 ON table1.column_name = table2.column_name;
解决方案: SELECT i.instituteId,i.instituteName,i.description,v.name,v.review,v.timestamp 从机构i INNER JOIN审查v on i.instituteId = v.instituteId 我在哪里(' 1',' 2',' 3')和v.instituteId = 1 ORDER BY v.timestamp DESC LIMIT 1;