Question

我有一个我想要运行的视频名称列表但不知道如何一个接一个地自动运行视频

function theFunction(video_id,user_id){
    var user_id1=$('#video_lesson_'+video_id).val();
    $.ajax({
                url:'video_selection.php',
                type:'POST',
                dataType:'json',
                 data: {'user_id1':user_id1,'video_id':video_id},
                success: function (data) {
                    var text="";
                    for (var i =0; i <= data.length; i++) {
                        var source="uploads/"+data[i];
                        var source1="uploads/"+data[i+1];
                       $("a[href='source']").attr('href', 'source1');

                    }


                }
            });
}

这是我的Html代码

 <a  video_id="<?php echo $f['id']; ?>" user_id="<?php echo $rows['id'];?>"   onclick="theFunction(this.getAttribute('video_id','user_id'))"  href="uploads/<?php echo $f['file_path'];?>" class="popup-youtube start-btn "><span>Start</span></a>

Answer 1

您应该source和source1作为变量，但是您在单引号内使用，因此这些被视为字符串。

替换此行

$("a[href='source']").attr('href', 'source1');

到这个

$("a[href='"+source+"']").attr('href', source1);

Answer 2

File f = new File("route.txt");
Scanner s = new Scanner(new FileInputStream(f));
s.useDelimiter("]],");
while (s.hasNext()) {
    String r = s.next();
    System.out.println(r);
}

Answer 3

我已经创建了如下示例代码，它可能会对您有所帮助：

<video width="256" height="192"  id="myVideo" controls autoplay>
    <source src="" id="mp4Source" type="video/mp4">
    Your browser does not support the video tag.
</video>

<script type="text/javascript">
    var i = 0;
    var videoCount = 0;
    var player = document.getElementById('myVideo');
    var mp4Vid = document.getElementById('mp4Source');
    var arr_video = new Array();

    $.ajax({
        url:'video_selection.php',
        type:'POST',
        dataType:'json',
        data: {'user_id1':user_id1,'video_id':video_id},
        success: function (data) {
            if (data != 'undefined') {
                arr_video = data;
                videoCount = arr_video.length;              
                videoPlay(0);
                player.addEventListener('ended', myHandler, false);
            }
        }
    });

     // Set video source and start autoplay     
    function videoPlay(num) {
        $(mp4Vid).attr('src', "/uploads/" + arr_video[num]);
        player.load();
        player.play();
   }

   // Continuously play videos one after another
   function myHandler() {
    i++;
    if(i == (videoCount - 1)){
        i = 0;
        videoPlay(i);
    }
    else{
        videoPlay(i);
    }
   }
</script>

使用javascript和PHP连续播放视频

3 个答案: