我试图在我的PyQt(pyqtgraph)应用程序中显示stdout和stderr。如果我按照Ferdinand Beyer对question的回答,我能够这样做。
但是,当我尝试通过更改write()函数内的文本来在stdout之前附加时间戳
new_text = '{}> {}'.format(time.strftime('%X'), old_text)
我的时间戳附加之前和之后 stdout消息。我对这种行为感到困惑,未能弄清楚它为什么会发生以及如何防止它。
更新:我的代码直接:
from pyqtgraph.Qt import QtGui,QtCore
from pyqtgraph.dockarea import DockArea,Dock
import pyqtgraph as pg
import sys
import time
app = QtGui.QApplication([])
win = QtGui.QMainWindow()
win.resize(300,300)
area = DockArea()
win.setCentralWidget(area)
d1 = Dock("cmd output", size=(300,300))
area.addDock(d1)
w1 = pg.LayoutWidget()
gui_cmd_bw = QtGui.QTextBrowser()
w1.addWidget(gui_cmd_bw,0,0)
d1.addWidget(w1)
class EmittingStream(QtCore.QObject):
textWritten = QtCore.pyqtSignal(str)
def write(self, text):
self.textWritten.emit(str(text))
def normalOutputWritten(text):
"""Append text to the QTextEdit."""
# this works without problems.
#gui_cmd_bw.insertPlainText(text)
timestamp = '{}> '.format(time.strftime('%X'))
# this adds timestamp before and after the stdout
gui_cmd_bw.insertPlainText(timestamp+text)
# this produces similar result
#gui_cmd_bw.append(timestamp+text)
# cmd output to application browser
sys.stdout = EmittingStream(textWritten=normalOutputWritten)
sys.stderr = EmittingStream(textWritten=normalOutputWritten)
win.show()
if __name__ == '__main__':
if (sys.flags.interactive != 1) or not hasattr(QtCore, 'PYQT_VERSION'):
print('stdout text')
QtGui.QApplication.instance().exec_()
最终输出如下:
14:15:16> stdout text
14:15:16>
答案 0 :(得分:0)
我找到了解决问题的快速解决方法,这对我来说已经足够了。
由于print()
函数每次输出调用sys.stdout.write()
两次,我添加条件以检查此输出是否为空。
def normalOutputWritten(text):
"""Append text to the QTextEdit."""
timestamp = '{}> '.format(time.strftime('%X'))
if len(text)>1:
text = timestamp+text
gui_cmd_bw.insertPlainText(text)
这将删除第二个时间戳。当然,一个符号输出中缺少时间戳。