将位置参数传递给funtion

Question

尝试将参数传递给函数时遇到错误。

    #! /usr/local/bin/bash
    program=$(basename $0)
    file_info () {
        # file_info: function to display file infomation.
        echo "this is $1" 
        if [[ -e $1 ]]; then
            echo "Paramater 1 eq $1"
            echo -e "\nFile Type:"
            file "$1"
            echo -e "\n File Status:"
            stat "$1"
        else
            echo "$program: usage: $program file" >&2
            return 1
        fi 
    }
    file_info

我测试了

    $ bash file_info.sh answer.sh
    this is .
    file_info.sh: usage: file_info.sh file

然而文件存在。

    $ [[ -e answer.sh ]] && echo "answer.sh exists"
    answer.sh exists

如何将位置参数传递给函数。

Answer 1

要将脚本参数传递给函数，请将最后一行更改为：

file_info "$@"