Question

撰写查询以获取大多数货件发送的星期几。例如，我们在星期五发送大部分货物。

SELECT 
    DATEPART(DW, [ShipDate]) AS 'Day', 
    COUNT(*) AS 'Number of shipments/per day'
FROM   
    [Purchasing].[PurchaseOrderHeader]
WHERE  
    [ShipDate] IS NOT NULL
GROUP BY
    DATEPART(DW, [ShipDate])
ORDER BY 
    Day;

我得到了这个结果：

Day    Number of shipments/per day
------------------------------------
1      693
2      164
3      232
4      728
5      577
6      842
7      776

Answer 1

使用derived table，case statement和concat尝试此操作，否则请使用其他concatenation method

select 
concat ('We sent most shipments on ',
(case DD
  when 1 then 'Sunday'
  when 2 then 'Monday'
  when 3 then 'Tueday'
  when 4 then 'Wednesday'
  when 5 then 'Thursday'
  when 6 then 'Friday'
  else
    'Saturday'
  end
  )) result

 from
(
SELECT top 1 DATEPART(DW, [ShipDate]) AS 'DD', COUNT(*) cnt
FROM   [Purchasing].[PurchaseOrderHeader]
WHERE  [ShipDate] IS NOT NULL
Group by DATEPART(DW, [ShipDate])
order by cnt desc
) x

大多数发货日

1 个答案: