Question

我有一个可以这样概括的数据库：

teacher (tid, f_name, l_name);
subject (sid, title);
teacher_subject (tid, sid);

我想要的是获得教授最多科目的老师，我在这里看到了一些类似但不重复的问题，并且无法修补解决方案以达到我想要的目标，这就是我和＃39;撰写：

select max(num_subs) from
   (select t.f_name, t.l_name, count(t.tid) num_subs
    from teacher t
    join teacher_subject ts
    on t.tid = ts.tid
    group by t.tid)
max_subs;

但无法继续下去。我确信它有办法实现它，因为我有时候离它太近但从未到达。

Answer 1

由于缺少窗口函数或允许绑定的限制条款，这在MySQL中有点尴尬，但是在这里你可以：

select *
from teacher 
where tid in
(
  select tid
  from teacher_subject
  group by tid
  having count(*) =
  (
    select count(*)
    from teacher_subject
    group by tid
    order by count(*) desc
    limit 1
  )
);

仅仅为了记录，在标准SQL中这仅仅是：

select *
from teacher t
order by (select count(*) from teacher_subject ts where ts.tid = t.tid) desc
fetch first 1 row with ties;

选择具有最大值的行（值由连接生成）

1 个答案: