Question

我有一个场景，我需要根据一个人的多个属性“匹配”记录。例如，如果FirstName和LastName匹配，或者NickName和LastName匹配，则应将这两个场景分组为一个较大的匹配。这是SQLFiddle中的示例数据： http://www.sqlfiddle.com/#!18/0ca91/7

我正在从记录属性生成匹配键。结果给了我两个不同的匹配键和三个总记录。我需要一个只生成一个匹配键的结果，最后我将在一个单独的步骤中将所有三个记录分组为一个黄金记录。我无法通过“分组依据”或使用DENSE_RANK来生成我的匹配键，从逻辑上将这些记录组合在一起。任何帮助将不胜感激！谢谢！

CREATE TABLE Persons (
    ID int,
    FirstName varchar(255),  
    LastName varchar(255),    
    NickName varchar(255)
);

INSERT INTO Persons
SELECT 1 AS ID, 'NIKKI' AS FNAME, 'MADISON' AS LNAME, 'Nikki' AS NickName
UNION ALL
SELECT 2 AS ID, 'NICOLE' AS FNAME, 'MADISON' AS LNAME, 'NICOLE' AS NickName
UNION ALL
SELECT  3 AS ID, 'NICOLE' AS FNAME, 'MADISON' AS LNAME,'Nikki' AS NickName

SELECT 
* 
, DENSE_RANK() OVER (ORDER BY TRIM(LastName), TRIM(FirstName)) AS GroupKey
FROM Persons

期望的结果：

GroupKey
1
1
1

Answer 1

 select distinct p1.*,
 DENSE_RANK() OVER (ORDER BY TRIM(p1.LastName)) AS GroupKey 
 from persons p1
 join persons p2 on (p1.FirstName = p2.FirstName or p1.FirstName = p2.nickname)

http://www.sqlfiddle.com/#!18/78705/6

通过多个分组在SQL Server中将记录匹配在一起

1 个答案: