我正在使用C#代码,我得到的JSON服务结果如下:
[
{"value":"{\"code\":\"MO\",\"description\":\"Monday\",\"isSet\":false}","nr":1}
,{"value":"{\"code\":\"TU\",\"description\":\"Tuesday\",\"isSet\":true}","nr":2}
]
我想使用此数组中的反序列化值对象列表。但我的印象是我的代码有点麻烦。
JArray j = JArray.Parse(task.Result);
List<Booking> b = j.Select(x => JObject.Parse(x["value"].ToString()).ToObject<Booking>()).ToList();
选择字符串并将它们解析为对象,然后真正按照这种方式进行转换?或者这可以更高效地完成吗?
答案 0 :(得分:1)
使用以下类:
public class Value
{
public string Code { get; set; }
public string Description { get; set; }
public bool IsSet { get; set; }
}
public class RootObject
{
[JsonProperty("Booking")]
public Value Value { get; set; }
public int Nr { get; set; }
}
然后反序列化您的JSON字符串,如下所示:
var test = JsonConvert.DeserializeObject<List<RootObject>>(json);
JSON字符串需要取消转义:
[
{"value":{"code":"MO","description":"Monday","isSet":false},"nr":1},
{"value":{"code":"TU","description":"Tuesday","isSet":true},"nr":2}
]
value
的问题也是双引号。删除它们,反序列化工作正常。
<强>更新强>
如果您不想操纵JSON字符串,可以将其反序列化两次。为此,我更改了类如下:
public class Value
{
public string Code { get; set; }
public string Description { get; set; }
public bool IsSet { get; set; }
}
public class RootObject
{
public string Value { get; set; }
public int Nr { get; set; }
}
public class ResultRootObject
{
public Value Value { get; set; }
public int Nr { get; set; }
}
然后我可以将其反序列化为ResultRootObject
:
var rootObjects = JsonConvert.DeserializeObject<List<RootObject>>(badJson, new JsonSerializerSettings());
var result = rootObjects.Select(item => new ResultRootObject
{
Value = JsonConvert.DeserializeObject<Value>(item.Value),
Nr = item.Nr
}).ToList();