Question

我可以绘制，选择和移动矩形和椭圆形等形状。

我也希望让用户调整自己的形状。

Private Sub createAVideo(ByVal imageInputfolderName As String, ByVal outVideoFileName As String, ByVal Optional fps As Single = 12F, ByVal Optional imgSearchPattern As String = "*.png") Dim vwriter As VideoWriter = New VideoWriter(outVideoFileName, New Accord.Extensions.Size(500, 500), fps, True) 'Make sure to change 500 with required height and width Dim ReadImg As Accord.Extensions.Imaging.ImageDirectoryReader = New ImageDirectoryReader(imageInputfolderName, imgSearchPattern) While ReadImg.Position < ReadImg.Length Dim i As IImage = ReadImg.Read() vwriter.Write(i) End While vwriter.Close() End Sub的代码：

MouseEvents

我知道我必须向public void mousePressed(MouseEvent e) { start = new Point(e.getX(), e.getY()); end = start; if(buttonState == 5) { for(int i = 0; i <shapes.size(); i++) { if(shapes.get(i).contains(start)) { shapeNumber = i; if(shapes.get(i) instanceof Rectangle2D) { handleRect = shapes.get(i).getBounds2D(); handleShape = handleRect; } else if(shapes.get(i) instanceof Ellipse2D) { handleCircle = new Ellipse2D.Double(shapes.get(i).getBounds2D().getX(), shapes.get(i).getBounds2D().getY(), shapes.get(i).getBounds2D().getWidth(), shapes.get(i).getBounds2D().getHeight()); handleShape = handleCircle; } delta = new Point(e.getX() - (int)handleShape.getBounds2D().getX(), e.getY() - (int)handleShape.getBounds2D().getY()); } } repaint(); } } public void mouseReleased(MouseEvent e) { Shape aShape = null; if (buttonState == 1) { aShape = drawCircle(start.x, start.y,e.getX(), e.getY()); } else if (buttonState == 2) { aShape = drawRectangle(start.x, start.y,e.getX(), e.getY()); } if(aShape !=null) { shapes.add(aShape); } start = null; end = null; handleShape = null; repaint(); } } ); this.addMouseMotionListener(new MouseMotionAdapter() { public void mouseDragged(MouseEvent e) { end = new Point(e.getX(), e.getY()); if(buttonState == 5) { int x = e.getX() - delta.x; int y = e.getY() - delta.y; if(handleShape instanceof Rectangle2D) { handleRect.setRect(x, y, handleShape.getBounds2D().getWidth(), handleShape.getBounds().getHeight()); handleShape = handleRect; } else if(handleShape instanceof Ellipse2D) { handleCircle.setFrame(x, y, handleShape.getBounds2D().getWidth(), handleShape.getBounds().getHeight()); handleShape = handleCircle; } } repaint(); } });和MousePressed添加一些内容，这些内容会占用所选形状的点数。这样我就可以拖动它来使形状更小或更大。

有人可以帮我吗？提前谢谢。

Answer 1

参考此link中的代码，我在下面的代码中解决了两个缺点。您还需要考虑进一步的考虑因素：

您使用多个2D形状（提及矩形和椭圆形）。但是这里的代码只显示了其中的一个。您需要对其进行处理，以便一次支持多个。
以下解决方案适用于单个象限中的形状移动。因此，需要有关边界的其他工作等。
此解决方案显示椭圆。您只需更改一行（至）Rectangle2D s = new Rectangle2D.Double();

以下是包含增强和评论的工作代码：

import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.event.MouseAdapter;
import java.awt.event.MouseEvent;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Point2D;
import java.awt.geom.Rectangle2D;

import javax.swing.JFrame;
import javax.swing.JPanel;

public class ResizeRectangle extends JPanel {
  private int SIZE = 8;
  //Below are 3 points, points[0] and [1] and top-left and bottom-right of the shape.
  // points[2] is the center of the shape
  private Rectangle2D[] points = { new Rectangle2D.Double(50, 50,SIZE, SIZE), 
                                   new Rectangle2D.Double(150, 100,SIZE, SIZE),
                                   new Rectangle2D.Double(100, 75,SIZE, SIZE)};
  Ellipse2D s = new Ellipse2D.Double();

  ShapeResizeHandler ada = new ShapeResizeHandler();

  public ResizeRectangle() {
    addMouseListener(ada);
    addMouseMotionListener(ada);
  }

  public void paintComponent(Graphics g) {
    super.paintComponent(g);

    Graphics2D g2 = (Graphics2D) g;

    for (int i = 0; i < points.length; i++) {
      g2.fill(points[i]);
    }
    s.setFrame(points[0].getCenterX(), points[0].getCenterY(),
        Math.abs(points[1].getCenterX()-points[0].getCenterX()),
        Math.abs(points[1].getCenterY()- points[0].getCenterY()));
    g2.draw(s);
  }

  class ShapeResizeHandler extends MouseAdapter {

    private Point2D[] lastPoints = new Point2D[3];
    private int pos = -1;
    public void mousePressed(MouseEvent event) {
      Point p = event.getPoint();

      for (int i = 0; i < points.length; i++) {
        if (points[i].contains(p)) {
          pos = i;
          // initialize preDrag points
          for(int j = 0; j < 3; j++){
              lastPoints[j] = new Point2D.Double(points[j].getX(), points[j].getY());
          }
          return;
        }
      }
    }

    public void mouseReleased(MouseEvent event) {
      pos = -1;
    }

    public void mouseDragged(MouseEvent event) {
      if (pos == -1)
        return;
      if(pos != 2){ //if 2, it's a shape drag
          points[pos].setRect(event.getPoint().x,event.getPoint().y,points[pos].getWidth(),
              points[pos].getHeight());
          int otherEnd = (pos==1)?2:1; //Get the end other than what is being dragged (top-left or bottom-right)
          //Get the x,y of the centre of the line joining the 2 new diagonal vertices, which will be new points[2]
          double newPoint2X = points[otherEnd].getX() + (points[pos].getX() - points[otherEnd].getX())/2;
          double newPoint2Y = points[otherEnd].getY() + (points[pos].getY() - points[otherEnd].getY())/2;
          points[2].setRect(newPoint2X, newPoint2Y, points[2].getWidth(), points[2].getHeight());
      }
      else{ //Shape drag, 1,2,3 points/marker rects need to move equal amounts
          Double deltaX = event.getPoint().x - lastPoints[2].getX();
          Double deltaY = event.getPoint().y - lastPoints[2].getY();
          for(int j = 0; j < 3; j++)
              points[j].setRect((lastPoints[j].getX() + deltaX),(lastPoints[j].getY() + deltaY),points[j].getWidth(),
                  points[j].getHeight());

      }
      repaint();
    }
  }

  public static void main(String[] args) {

    JFrame frame = new JFrame("Resize Shape2D");

    frame.add(new ResizeRectangle());
    frame.setSize(300, 300);
    frame.setLocationRelativeTo(null);
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    frame.setVisible(true);
  }
}

希望这有帮助。

Java使用鼠标调整形状大小

1 个答案: