转换低于非从EDW到Hive

Question

select source_type, data_load_type from wc_table_inf 
where not (source_type IN ('EHUB','FOCUS','SAPReport') 
and data_load_type in ('FULL','INCR'));

这是一个EDW查询。我需要在hive中使用等效查询。我怎么能解决这个问题？

Answer 1

试试这个。

select source_type, data_load_type from wc_table_inf where source_type not in ('EHUB','FOCUS','SAPReport') and data_load_type not in ('FULL','INCR');

Answer 2

您必须展开布尔逻辑NOT (A and B) = NOT A OR NOT B

SELECT source_type
    ,data_load_type
FROM wc_table_inf
WHERE source_type NOT IN (
        'EHUB'
        ,'FOCUS'
        ,'SAPReport'
        )
    OR data_load_type IN (
        'FULL'
        ,'INCR'
        );