Question

我正在尝试做一个简单的订购系统。其中服务已经在数据库中，但是如果手动输入了执行该服务的人员的名称。我能够成功保存订单但是参加客户的人的姓名，但是我遇到麻烦，如果我在一个约会中有多个服务，那么只保存我输入名字后的第一个名字，而不是保存到我的名字中数据库。这是我正在研究的功能

function ConfirmOrder(){
  var orders = {}; 


  if($('.food').length>0){
    var checkbox = 0;

    $('tr.item').each(function(){
      var order_id = $(this).attr('id');
      var quantity1 = $(this).find('.quantity').text();
      var name = $('#name').val();


      orders[order_id] = quantity1;

      })

   console.log(orders);


      if ($('#senior-checkbox').prop('checked')) {
        checkbox = 1;
      }
      else{
        checkbox = 0;
      }

   }

  else{
    alert("No orders taken");

  }
    $.ajax({
      url: "confirm_order.php",
      type: "POST",
      async: true,
      cache: false,
      data: {orders:orders,checkbox:checkbox,name},

      success: function(html){

     }
   })

这是我如何选择服务并输入名称

<?php
include 'dbconnection.php';
$menu_id = $_POST['menu_id'];
$query = mysql_query("SELECT * FROM menu WHERE menu_id=$menu_id");
echo "SELECT * FROM menu WHERE menu_id=$menu_id";

while ($row = mysql_fetch_array($query)){

?>
<tr id="<?php echo $row['menu_id'];?>" class="item">
    <td class="food noprint" id="<?php echo $row['menu_id'];?>">
        <input name="checkbox[]" type="checkbox" value="<?php echo $row['menu_id'];?>">

    </td>
    <td><?php echo $row['dish'];?></td>
    <td class="food_price_column" id="<?php echo $row['menu_id'];?>">


<span>
    <span class="btn btn-success noprint" onclick="minusQuantity(<?php echo $row['menu_id'];?>, <?php echo $row['price']; ?>)"><i class="fa fa-minus"></i></span>

&nbsp;&nbsp;&nbsp;&nbsp; <span class="quantity order-quantity<?php echo $row['menu_id'];?>">1</span> 

    &nbsp;&nbsp;&nbsp;&nbsp; <span class="btn btn-success noprint" onclick="addQuantity(<?php echo $row['menu_id'];?>, <?php echo $row['price']; ?>)"><i class="fa fa-plus"></i></span></span>

    </td>
    <td><?php echo $row['price'];?></td>
    <td class="price" id="<?php echo $row['menu_id'];?>"><?php echo $row['price'];?></td>
    <td><input type="text" name="name" id="name"></td>
    </td></tr>

<?php } ?>

这就是我将它保存到数据库的方式

<?php
include 'dbconnection.php';
session_start();

$user_id = $_SESSION['user_id'];

if(isset($_POST['orders'])){
    $checkbox = $_POST['checkbox'];
    $order_id = $_POST['orders'];
    $fullname= "";
    $last_ids = [];
    $name = $_POST['name'];



    //alert($name);

    //Query the cashier's name to  be inserted to sales table
    $user_query = mysql_query("SELECT full_name FROM account WHERE acct_id = $user_id");
    while($row = mysql_fetch_array($user_query)){
        $fullname = $row['full_name'];
    }

    //insert orders into orders table
        $insert = mysql_query("INSERT INTO sales VALUES ('','$fullname',now(),$checkbox)");

        if($insert){
            $last_id = mysql_insert_id();
        }
    foreach($order_id as $key => $value) { //$key = dish_id and $value = quantity


        $dish_query = mysql_query("SELECT dish FROM menu WHERE menu_id = $key");
        while($dish = mysql_fetch_array($dish_query)){

            $dish = $dish['dish'];
            /*$name = $_POST['name'];*/
            $order = mysql_query("INSERT INTO orders VALUES ('', '$dish','$value','$last_id','$name')");

            $query1 = mysql_query("INSERT into a_logs(id,name,activity,a_date) values(0,'$fullname','Added $dish',NOW())");


            $recent_order_id = mysql_insert_id();

        }       
    }
}

?>

Answer 1

这是您需要检查的代码部分：

    </td>
    <td><?php echo $row['price'];?></td>
    <td class="price" id="<?php echo $row['menu_id'];?>"><?php echo $row['price'];?></td>
    <td><input type="text" name="name" id="name"></td>
    </td>
    </tr>

当您使用while循环创建输入标记时，每个标记都将具有相同的名称和ID。因此，当您使用id获取数据时，每次只会给您一个值。

您可以使用以下内容：创建值数组并访问它们

while(-->condition<--){
</td>
        <td><?php echo $row['price'];?></td>
        <td class="price" id="<?php echo $row['menu_id'];?>"><?php echo $row['price'];?></td>
        <td><input type="text" name="name[]" ></td>
        </td>
        </tr>
}

使用php访问值：

$name = $_POST['name'];

foreach( $name as $v ) {
print $v;
}

简单的订购系统

1 个答案: