多选命令替代ifs竞赛

Question

bash中有一个方便的多项选择命令case，简化了条件逻辑。

假设有这样一个小型脚本：

    read -p "Enter selection [0-2]: " num
    if [[ $num =~ ^[0-2]$ ]]; then
        if [[ $num == 0 ]]; then 
            echo "num eq 0"
        fi
        if [[ $num == 1 ]]; then 
            echo "num eq 1"
        fi 
        if [[ $num == 2 ]]; then 
            echo "num eq 1" 
        fi 
    else
        echo "Invalid Entry." >&2
        exit 1
    fi

它可以重构为

    read -p "Enter selection [0-2]: " num
    case $num in 
        0)  echo "num eq 0" ;;
        1)  echo "num eq 1" ;;
        2)  echo "num eq 2" ;;
        *)  echo "Invalid Entry." >&2
            exit 1 ;; 
    esac      

Python不包含内置的多个选项

    num=int(input( "Enter selection [0-2]: "))
    if num == 0:
        print( "num eq 0")
    elif num == 1:
        print( "num eq 1")
    elif num == 2:
        print( "num eq 2")
    else:
        print( "Invalid Entry.")

如何使用python以类似案例的方式实现这样的逻辑？