我有CutomerType对象和Customer对象的列表。 Customer对象上有cutomerType id属性。根据客户对象上的客户类型ID,我必须循环或映射正确的customerType对象并取消显示名称代码。
[ {
"id" : "5436d5fd-e3ea-4e09-be4a-a80967cd72e5",
"code" : "0",
"name" : "UN"
}, {
"id" : "674b76b8-f1ac-5c14-e053-ce5e1cac867d",
"code" : "1",
"name" : "NON-UN"
}, {
"id" : "674b76b8-f1ad-5c14-e053-ce5e1cac867d",
"code" : "2",
"name" : "COS-UN"
}, {
"id" : "674b76b8-f1ae-5c14-e053-ce5e1cac867d",
"code" : "NA",
"name" : NA"
} ]
Customer
{
"id" : "1",
"name": "Jhon",
"type": "5436d5fd-e3ea-4e09-be4a-a80967cd72e5",
}

答案 0 :(得分:1)
希望这很清楚,如果不随意问
const loop = // whole array;
const customer = // customer object
loop.find(el => el.id === customer.type).name
答案 1 :(得分:1)
这就是你能做的。
const customerCodeArray = [{
"id": "5436d5fd-e3ea-4e09-be4a-a80967cd72e5",
"code": "0",
"name": "UN"
}, {
"id": "674b76b8-f1ac-5c14-e053-ce5e1cac867d",
"code": "1",
"name": "NON-UN"
}, {
"id": "674b76b8-f1ad-5c14-e053-ce5e1cac867d",
"code": "2",
"name": "COS-UN"
}, {
"id": "674b76b8-f1ae-5c14-e053-ce5e1cac867d",
"code": "NA",
"name": "NA"
}]
const customer = {
"id": "1",
"name": "Jhon",
"type": "5436d5fd-e3ea-4e09-be4a-a80967cd72e5",
};
const getCustomerCode = (type) => {
const filterList = customerCodeArray.filter((obj) => obj.id === type);
if (filterList.length > 0) {
return filterList[0];
}
}
console.log(getCustomerCode(customer.type));
答案 2 :(得分:0)
const filteredResult = customerCodeArray.filter(type => type.id === Customer.type);
console.log(filteredResult[0].name);