Question

我正在使用SSRS PowerShell cmdlet将所有SSRS报告移至新服务器。现在，我正在尝试重新创建新报告服务器上已存在的文件层次结构。

为了做到这一点，我正在通过我在PC上创建的报告文件夹的本地副本进行递归。使用New-RsFolder函数，我可以创建第一级文件夹，但是一旦到达任何类型的子目录，脚本就会失败。

Import-Module ReportingServicesTools
$ReportPath = 'C:\MyFiles\SSRS 2016 Upgrade\Reporting Server\' 
$Folders = Get-ChildItem $ReportPath -Recurse -Directory

foreach($Folder in $Folders){
    $SubFolderPath = ''
    $arrSubFolders = $Folder.FullName.Replace($ReportPath, '').Split('\')
    foreach($SubFolder in $arrSubFolders){
        $SubFolderPath += '/'
        try{
            New-RsFolder -ReportServerUri $ReportServerURI -FolderName $SubFolder -RsFolder $SubFolderPath
            Write-Host "Created folder $($SubFolderPath)/$($SubFolder)"
        }
        catch{
            Write-Host "Folder $($SubFolderPath)/$($SubFolder) exists"
        }
        $SubFolderPath += $SubFolder
    }
}

当我回到会计时，脚本开始捕获该文件夹已存在，如下所示：

Created folder //Accounting
Created folder //Customer Service
Created folder //Dashlets
Created folder //Data Sources
Created folder //DataSets
Created folder //Forms
Created folder //Human Resources
Created folder //Information Technology
Created folder //Integrated
Created folder //Maintenance
Created folder //Management
Created folder //Old Reports
Created folder //Operations
Created folder //Owner Operator Settlements
Created folder //Report Parts
Created folder //Safety and Recruiting
Folder //Accounting exists
Folder /Accounting//PnG Proposal and Payment exists
Folder //Accounting exists
Folder /Accounting//PTI Logistics exists
Folder //Accounting exists
Folder /Accounting//Settlements exists
Folder //Accounting exists
Folder /Accounting//XRS exists
Folder //Accounting exists
Folder /Accounting//PTI Logistics exists
Folder /Accounting/PTI Logistics//PTI Logistics - Settlements exists
Folder //Accounting exists
Folder /Accounting//PTI Logistics exists
Folder /Accounting/PTI Logistics//PTI Logistics - Settlements exists
Folder /Accounting/PTI Logistics/PTI Logistics - Settlements//Drill-Through exists
Folder //Accounting exists
Folder /Accounting//Settlements exists
Folder /Accounting/Settlements//Drill-Through exists
Folder //Accounting exists
Folder /Accounting//Settlements exists
Folder /Accounting/Settlements//TMW Templates exists
Folder //Customer Service exists

递归从来都不是我的强项，所以如果有人能对此有所了解，我会很感激。

Answer 1

Get-ChildItem -Recurse枚举目标目录树，其父路径位于其后代之前。

此外，您可以使用-Name开关输出目录＆＃39; path strings ，相对于目标目录。

这意味着您可以专注于逐个创建每个文件夹，依靠其祖先路径预先存在（在/的情况下）或在之前的迭代中创建：

Import-Module ReportingServicesTools
$ReportPath = 'C:\MyFiles\SSRS 2016 Upgrade\Reporting Server' 

Get-ChildItem $ReportPath -Recurse -Directory -Name | ForEach-Object {
  # Split the relative input path into leaf (directory name)
  # and parent path, and convert the parent path to the target parent path
  # by prepending "/" and converting path-internal "\" instances to "/".
  $SubFolderParentPath = '/' + ((Split-Path -Parent $_) -replace '\\', '/')                            #'
  $SubFolderName = Split-Path -Leaf $_
  try{
    New-RsFolder -ReportServerUri $ReportServerURI -Path $SubFolderParentPath -FolderName $SubFolderName 
    Write-Host "Created folder ${SubFolderPath}/${SubFolder}"
  }
  catch {
      # Report the specific error that occurred, accessible via $_
      Write-Host "An error occurred for ${SubFolderPath}/${SubFolder}: $_"
  }
}

这种方法不仅比你的方法更有效，而且还避免了多次创建祖先路径的尝试。

注意：

使用-Path而不是-RsFolder，因为作为New-RsFolder available in the PowerShell Gallery一部分的ReportingServices module版本仅支持-Path来指定目标location（文件夹）。
catch块现在报告发生的实际错误（$_），因为特定问题可能是其他而不是预先存在的文件夹。
请务必使用-Path启动传递给/的目标路径。

使用PowerShell中的New-RsFolder递归创建文件夹层次结构

1 个答案: