Question

我想从节点对列表及其权重中创建字典数组的字典。

nets = pd.read_table('data/nodes.txt', header = None)
bb = np.array(nets).tolist()
graph = collections.defaultdict(dict)

for row in bb:
    graph[row[0]][row[1]]=row[2]
    graph[row[1]][row[0]] = row[2]

print(dict(graph))

导致了这本词典

{0: {1: 2, 2: 3, 3: 6, 7: 8}, 1: {0: 2, 2: 5, 4: 7}, 2: {0: 3, 1: 5, 11: 5, `5: 4}, 3: {0: 6, 11: 4, 6: 2}, 4: {1: 7}, 5: {8: 3, 2: 4}, 6: {9: 3, 3: 2}, 7: {0: 8}, 8: {5: 3}, 9: {10: 6, 6: 3}, 10: {9: 6}, 11: {2: 5, 3: 4}}`

并希望以此形式使用它。

{0: [{1: 2}, {2: 3}, {3: 6}, {7: 8}], 
1: [{0: 2}, {2: 5}, {4: 7}], 
2: [{0: 3}, {1: 5}, {11: 5}, {5: 4}],
3: [{0: 6}, {11: 4}, {6: 2}],
4: [{1: 7}], 
5: [{8: 3}, {2: 4}], 
6: [{9: 3}, {3: 2}], 
7: [{0: 8}, 8: {5: 3}], 
9: [{10: 6}, {6: 3}], 
10: [{9: 6}], 
11: [{2: 5}, {3: 4}]}

Answer 1

如果你真的想要，你可以很容易地做到这一点，虽然我会仔细查看你将使用这个数据结构的位置，看看你现有的更合理的结构是否可以制作而是工作。

无论如何，这是一个应该做你想做的快速实现：

graph = collections.defaultdict(list)

for row in bb:
    graph[row[0]].append({row[1]: row[2]})
    graph[row[1]].append({row[0]: row[2]})

我想创建一个字典列表的字典

1 个答案: