问题
我需要动画流畅,但它是逐帧绘制的。代码在Jupyter Notebook中运行。
以下是图书馆
struct user {
char id[10];
char name[25];
char group;
float score;
};
struct user list[25];
int registered = 0;
void createNewUser() {
struct user *userPtr, newUser;
userPtr = &newUser;
printf("\nId: ");
scanf("%10s", &(*userPtr).id);
printf("\nName: ");
scanf("%25s", &(*userPtr.name);
printf("\nGroup: ");
scanf("%c", &(*userPtr).group);
printf("\nScore: ");
scanf("%f", &(*userPtr).score);
insert(newUser);
printf("%10s\n", list[0].id);
printf("%25s\n", list[0].name);
printf("%c\n", list[0].group);
printf("%.1f\n", list[0].score);
}
void insert(struct user newUser) {
if (registered < 25){
list[registered] = newUser;
registered += 1;
}
}
创建函数以进行卷积
import numpy as np
from matplotlib import pyplot as plt
from scipy import signal as sp
这是绘图
t_ini=0
t_final = 11
dt=0.1
t = np.arange(t_ini,t_final,dt)
expo = np.exp(-t)*np.piecewise(t,t>=0,[1,0])
t1 = np.arange(0,10,0.1)
s = np.sin(t1)
conv_=sp.convolve(s,expo,'full')
n_conv=np.arange(min(t1)+min(t),max(t1)+max(t)+0.1,0.1)
y = [0] * len(conv_)
t2 = [0] * len(n_conv)
答案 0 :(得分:0)
matplotlib
提供了实例ArtistAnimation
,允许预先计算的图形的无缝动画。我刚给你的代码添加了几行代码。我改变的只是使用enumerate
来改进你的代码
import numpy as np
from matplotlib import pyplot as plt
from scipy import signal as sp
import matplotlib.animation as anim
t_ini=0
t_final = 11
dt=0.1
t = np.arange(t_ini,t_final,dt)
expo = np.exp(-t)*np.piecewise(t,t>=0,[1,0])
t1 = np.arange(0,10,0.1)
s = np.sin(t1)
conv_=sp.convolve(s,expo,'full')
n_conv=np.arange(min(t1)+min(t),max(t1)+max(t)+0.1,0.1)
y = [0] * len(conv_)
t2 = [0] * len(n_conv)
#prepare figure for display
fig = plt.figure()
ax = plt.axes()
#create list to collect graphs for animation
img = []
for i, x in enumerate(n_conv):
y[i] = conv_[i]
t2[i] = n_conv[i]
#append new graphs to list
newpic, = ax.plot(t2, y, c= "blue")
img.append([newpic])
#animate the list of precalculated graphs
ani = anim.ArtistAnimation(fig, img, interval = 50)
plt.show()
输出: