调用遗留方法来获取php中子类的名称

Question

我正在创建动态crud，但我希望将cast方法（数据库数组到当前类的对象）直接继承到我需要获取名称引用的子项，但是我继承了该方法的对象，如果我把它放在继承的类中，它的工作是完美的，但如果我有1万个继承的类，我必须复制1万次（那是我想要避免的）

<?php
namespace Models;
use Interfaces\ICrud;
use db\DBconection;
require('./interfaces/icrud.php');
require('./db/dbconnect.php');

abstract class Model implements ICrud{
    private $connection;
    protected $schema='public.';

    public function __construct(){
    }

    public function get($id){
        return (new DBconection())->runQuery("SELECT * from $this->schema".$this->getModelName(get_class($this))." WHERE id=$id");
    }




     public function create($entity){

    }

    public function update($entity){

    }

    public function delete($id){
        return (new DBconection())->runQuery("DELETE from $this->schema".$this->getModelName(get_class($this))." WHERE id=$id");            
    }



    private function getModelName($class){
        return strtolower(str_replace('Model','',(new \ReflectionClass($class))->getShortName()));
    }
}

这是儿童班

<?php
namespace Models;
use Models\Model,
    db\DBconection;
require('model.php');

class UsersModel extends Model {   
    private $id; 
    private $username;
    private $password;
    private $active;
    private $create;
    private $update;
    private $id_typeuser;
    private $id_people;
    protected $schema='security.';

    public function __construct(){

    }
}