我正在尝试使用formspree提交表单我遇到两个不同的错误。当我在刷新页面后尝试提交表单时,我在新页面上出现错误
无法发布/联系
当我回去尝试再次提交表单时,我在控制台中收到错误消息:
POST https://formspree.io/sheabathandbody@mail.com 400()jquery.min.js:4
发送@jquery.min.js:4
ajax @ jquery.min.js:4
(匿名)@main.js:8
dispatch @ jquery.min.js:3
r.handle @ jquery.min.js:3
我之前使用过此方法/代码提交表单,所以我不知道问题是什么
Contact.vue表格
<form id="contact" name="contact-form" method="post" action = "">
<fieldset>
<input placeholder="Your name" name="name" type="text" id="name" tabindex="1" required="required">
</fieldset>
<fieldset>
<input placeholder="Your Email Address" name="email" id="email" type="email" tabindex="2" required="required">
</fieldset>
<fieldset>
<input placeholder="Your Phone Number (optional)" type="tel" tabindex="3">
</fieldset>
<fieldset>
<textarea placeholder="Type your message here...." tabindex="5" name="message" id="message" required="required"></textarea>
</fieldset>
<fieldset>
<button name="submit" type="submit" id="submit_btn" >Submit</button>
</fieldset>
</form>
这是我的main.js
(function($) {
$(window).on("load", function() {
// Contact form
var form = $("#contact");
form.submit(function(event) {
event.preventDefault();
var form_status = $('<div class="form_status"></div>');
$.ajax({
url: "https://formspree.io/sheabathandbody@mail.com",
method: "POST",
data: $(this).serialize(),
dataType: "json",
beforeSend: function() {
form.prepend(
form_status
.html(
'<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>'
)
.fadeIn()
);
}
}).done(function(data) {
form_status
.html(
'<p class="text-success">Thank you for contacting us. We will be in touch.</p>'
)
.delay(3000)
.fadeOut();
});
});
});
})(jQuery);
答案 0 :(得分:0)
猜猜这与VueJS无关,因为它不会在你共享的那些代码块中使用所有vue,这是纯粹的jQuery。
说,发送表单的问题是因为你没有正确地提交事件。
form.on('submit', function () { ... })
另一方面,ajax调用无法正常工作;你应该检查formspree.io的文档并更正它。
检查下一个代码
$(document).ready(function() {
// Contact form
var form = $("#contact");
form.on('submit', function(event) {
alert('Hola hola. This is working now!');
event.preventDefault();
var form_status = $('<div class="form_status"></div>');
$.ajax({
url: "https://formspree.io/sheabathandbody@mail.com",
method: "POST",
data: $(this).serialize(),
dataType: "json",
beforeSend: function() {
form.prepend(
form_status
.html(
'<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>'
)
.fadeIn()
);
}
}).done(function(data) {
form_status
.html(
'<p class="text-success">Thank you for contacting us. We will be in touch.</p>'
)
.delay(3000)
.fadeOut();
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="contact" name="contact-form" method="post" action="">
<fieldset>
<input placeholder="Your name" name="name" type="text" id="name" tabindex="1" value="blah" required="required">
</fieldset>
<fieldset>
<input value="email@email.com" placeholder="Your Email Address" name="email" id="email" type="email" tabindex="2" required="required">
</fieldset>
<fieldset>
<input value="123123123" placeholder="Your Phone Number (optional)" type="tel" tabindex="3">
</fieldset>
<fieldset>
<textarea placeholder="Type your message here...." tabindex="5" name="message" id="message" required="required">Damn</textarea>
</fieldset>
<fieldset>
<button name="submit" type="submit" id="submit_btn">Submit</button>
</fieldset>
</form>
答案 1 :(得分:0)
您可以创建一个方法,例如 postNow。
methods: {
postNow() {
const link = "https://formspree.io/sheabathandbody@mail.com"
var data = new FormData();
data.append('_replyto',this.email)
data.append('message',this.message)
this.axios.post(link,data , {
headers: {
'Accept': 'application/json',
},
// body: data,
}).then(res =>{
console.log("response ===" ,res)
this.email = "" ;this.message=""; //don't forget to create your data
}).catch(err =>{
console.log(err)
});
}
},
在您的模板中,您可以使用简单的 HTML 表单,只需稍作调整,
<form @submit.prevent="postNow" method="POST" >
<label>
Your email:
<input type="email" name="_replyto" v-model="email" />
</label>
<label>
Your message:
<textarea name="message" v-model="message"></textarea>
</label>
<button type="submit">Send</button>
</form>