我正在尝试在表格单元格悬停时在鼠标旁边创建一个div弹出窗口。
<td onmouseover="bubblePopup("param1","param2");">This is the cell</td>
是否可以使用bubblePopup函数获取光标位置。
function bubblePopup(param1, param2){
var newdiv = document.createElement('div');
newdiv.setAttribute('id', param1);
newdiv.style.width = "200px";
newdiv.style.height = "80px";
newdiv.style.position = "absolute";
newdiv.style.left = cursorX + "px";
newdiv.style.top = cursorY + "px";
newdiv.innerHTML = "content";
document.body.appendChild(newdiv);
}
我更喜欢原生的javascript(但也会考虑jquery选项)。它只需要在Firefox 3.5及更高版本中运行。
答案 0 :(得分:4)
答案 1 :(得分:3)
var td = document.getElementById("thetd");
td.onmouseover = function(e){bubblePopup(e, 'param1','param2')};
function bubblePopup(e, param1, param2){
var newdiv = document.createElement('div');
newdiv.setAttribute('id', param1);
newdiv.style.width = 200;
newdiv.style.height = 80;
var cursorX = e.pageX,
cursorY = e.pageY;
newdiv.style.position = "absolute";
newdiv.style.left = cursorX + 'px';
newdiv.style.top = cursorY + 'px';
newdiv.innerHTML = "content";
document.body.appendChild(newdiv);
}