Question

从C转换到Java后，我了解到Java包含许多可以为您完成工作的功能，可以这么说，不像C中您必须手动完成任务。

我目前正在设计一款OOP棋盘游戏，其中允许多个玩家挑选一个在整个游戏中代表它们的游戏。我已将游戏片存放在一个阵列中，然后询问玩家的数量以选择一个游戏片。然而，由于显而易见的原因，他们不允许选择与他们之前的球员相同的比赛。因此，我的问题是有一个功能，允许我从阵列中删除一个挑选的游戏片，或者我必须手动执行此操作，可以这么说。如果需要，我的代码如下：

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Answer 1

我会为当前玩家介绍一个新的List<String>可用选项：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

...

List<String> availableOptions = new ArrayList<>(
    Arrays.asList(potential_player_pieces)
);

并在选择完成后删除所选元素：

for (int i = 0; i < players; ++i) {
    System.out.println("Player " + i + " pick a playing piece: " + availableOptions);
    availableOptions.remove(player_pieces[i] = reader.nextLine());
}

您也可能将阵列的初始化时间缩短为：

String[] potentialPlayerPieces = new String[] {"*", "|", ..., "<"};

请注意，我已将该变量重命名为 Javaish 。

Answer 2

我想在你的案例中建议HashMap。我认为这种数据结构是有效的，符合您的目的。

Map<String, Integer> pieceMap = new HashMap<String, Integer>();
// HashMaps stores the value as a key value format. 
// Here the keys are the piece options 
// And the 0 is indicating that, primarily the piece is not used. 
pieceMap.put("*", 0);
pieceMap.put("|", 0);
pieceMap.put("?", 0);
pieceMap.put("@", 0);
pieceMap.put("&", 0);
pieceMap.put("¬", 0);
pieceMap.put("!", 0);
pieceMap.put("%", 0);
pieceMap.put("<\n", 0);

String[] player_pieces = new String[players + 1]; 
for (int i = 0; i < players; i++) {
    System.out.print("Player " + i + " pick a playing piece:"); // Asks the players the question

    printAvailablePieces(pieceMap);

    String piecePlayed = reader.nextLine();

    if(pieceMap.containsKey(piecePlayed) && pieceMap.get(piecePlayed).equals(0)) {
        // The piece has not used yet. 
        pieceMap.put(piecePlayed, 1);
        player_pieces[i] = piecePlayed;
    } else {
        // The piece was played before
        System.out.println("Please play a different piece");
        i--; // Take the user input again. 
    }
}

public void printAvailablePieces(HashMap<String, Integer> pieceMap) {
    for (Map.Entry<String, Integer> entry : pieceMap.entrySet()) 
        if(entry.getValue().equals(0)) System.out.print(entry.getKey() + " ");
}

希望有所帮助。

Answer 3

我建议使用HashSet而不是数组来存储所有板块。一旦玩家选择了一件作品，就可以通过拨打remove轻松将其从集合中移除。您也可以通过调用集合上的contains方法来验证选择。

Answer 4

使用List和HashMap

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Scanner;

public class Temp {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        List<String> potential_player_pieces = new ArrayList<String>();//Array storing the playing pieces available
             potential_player_pieces.add("*");
             potential_player_pieces.add("|");
             potential_player_pieces.add( "?");
             potential_player_pieces.add( "@");
             potential_player_pieces.add( "&");
             potential_player_pieces.add( "¬");
             potential_player_pieces.add( "!");
             potential_player_pieces.add( "%");
             potential_player_pieces.add( "<\n");
             Collections.sort(potential_player_pieces);

             System.out.println(potential_player_pieces);

             int length=potential_player_pieces.size();
             Scanner reader= new Scanner(System.in);

           Map<Integer,String> player_pieces = new HashMap<Integer,String>();//String to store the playing pieces that the players have chosen
                 for (int i=1; i<=length; i++)//Loops to the number of players and  asks them what playing piece they want
                 {
                     System.out.print("Player " + i + " pick a playing piece: ");//Asks the players the question


                     for (int j=0; j<potential_player_pieces.size(); j++){

                            if(j==0) 
                            {
                                System.out.print(potential_player_pieces.get(0)+"\n");
                                player_pieces.put(i, potential_player_pieces.get(0));
                                potential_player_pieces.remove(0);

                            }
                            if(potential_player_pieces.size()>0)
                         System.out.println(potential_player_pieces.get(j)); //Displays the possible playing pieces


                     }

                      //Saves the player chioces to the array made above

                 }

                 System.out.println(player_pieces);

    }

}

使用Java从循环中的数组中删除元素

4 个答案: