Question

我已多次检查代码，但无法找到错误！ issetCookie在这里返回false。

<html>
 <body>
   <?php if(!isset($_REQUEST['sub'])) { ?>
   <form name="f1" action="1.php" method="post">
     Name : <input type="text" name="na"><br>
     Last Name : <input type="text" name="lna"><br>
     Email Id : <input type="text" name="eml"><br>
     Phone No : <input type="text" name="phn"><br>
     City : <input type="text" name="cty"><br>
     <input type="Submit" name="sub" value="ok"><input type="Reset" name="res" value="Clear">
  <?php } else {
     $name=$_REQUEST['na'];
     $lname=$_REQUEST['lna'];
     $email=$_REQUEST['eml'];
     $phone=$_REQUEST['phn'];
     $city=$_REQUEST['cty'];

     setcookie("Name", $name, time()+3600, "/","", 0);
     setcookie("LName",$lname);
     setcookie("Email",$email);
     setcookie("Phone",$phone);
     setcookie("City",$city);
  } ?>
  </form>
 </body>
</html>

有人可以帮我为Cookie分配变量吗？如果是else的问题，请建议使用表单数据分配cookie值并在表单操作中定义的下一页上检索的备用选项。

Answer 1

因为你试图在else条件中设置cookie。所以变量在else条件中不存在，因为表单未提交。你需要像这样添加过期时间。

setcookie("Name", $name, time() + (86400 * 30), "/");// one day

并像这样检查

if(!isset($_COOKIE['Name'])) {
         echo "Cookie named  is not set!";
    } else {
         echo "Cookie  is set!<br>";
         echo "Value is: " . $_COOKIE['Name'];
    }

你的代码应该是这样的

<?php
if (isset($_POST['sub'])) {
    $name=$_POST['na'];
    $lname=$_POST['lna'];
    $email=$_POST['eml'];
    $phone=$_POST['phn'];
    $city=$_POST['cty'];
    setcookie("Name", $name, time() + (86400 * 30), "/");
}
if(!isset($_COOKIE['Name'])) {
     echo "Cookie named  is not set!";
} else {
     echo "Cookie  is set!<br>";
     echo "Value is: " . $_COOKIE['Name'];
}
?>
<html>
<body>
     <form name="f1" action="1.php" method="post">
     Name : <input type="text" name="na"><br>
     Last Name : <input type="text" name="lna"><br>
     Email Id : <input type="text" name="eml"><br>
     Phone No : <input type="text" name="phn"><br>
     City : <input type="text" name="cty"><br>
     <input type="Submit" name="sub" value="ok"><input type="Reset" 
     name="res" 
     value="Clear">
    </form>
</body>
</html>

Answer 2

像这样使用。

public class News_Yeb extends Fragment implements OnClickListener {
    String DataParseUrl = "http://fitandfineindustries.com.np/insert.php" ;
    Boolean CheckEditText ;
    private static View view;
    EditText name,email,contact ;
    String Getname,GetEmail,GetContact ;
    private static Button signUpButton;

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        view = inflater.inflate(R.layout.news_yeb, container, false);
        initViews();
        setListeners();
        return view;
        }

    // Initialize all views
    private void initViews() {
        name = (EditText) view.findViewById(R.id.fullName);
        email = (EditText) view.findViewById(R.id.userEmailId);
        contact = (EditText) view.findViewById(R.id.mobileNumber);
        signUpButton = (Button) view.findViewById(R.id.signUpBtn);

    }

    // Set Listeners
    private void setListeners() {
        signUpButton.setOnClickListener(this);
    }

    @Override
    public void onClick(View v) {
        GetCheckEditTextIsEmptyOrNot();


        if(CheckEditText){

            SendDataToServer(Getname, GetEmail, GetContact);

        }
        else {

            Toast.makeText(getActivity(), "Please fill all form fields.", Toast.LENGTH_LONG).show();

        }
    }


    // Check Validation Method
    private void GetCheckEditTextIsEmptyOrNot() {

        // Get all edittext texts
        String Getname  = name.getText().toString();
        String GetEmail  = email.getText().toString();
        String GetContact = contact.getText().toString();

        if(TextUtils.isEmpty(Getname) || TextUtils.isEmpty(GetEmail) || TextUtils.isEmpty(GetContact))
        {

            CheckEditText = false;

        }
        else {

            CheckEditText = true ;
        }

    }

    public void SendDataToServer(final String name, final String email, final String contact){
        class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {
            @Override
            protected String doInBackground(String... params) {

                String QuickName = name ;
                String QuickEmail = email ;
                String QuickContact = contact;

                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

                nameValuePairs.add(new BasicNameValuePair("name", QuickName));
                nameValuePairs.add(new BasicNameValuePair("email", QuickEmail));
                nameValuePairs.add(new BasicNameValuePair("contact", QuickContact));

                try {

                    HttpPost httpPost = new HttpPost(DataParseUrl);

                    httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                    URL url = new URL("http://fitandfineindustries.com.np/insert.php");
                    URLConnection urlConnection = (HttpURLConnection) url.openConnection();


                } catch (ClientProtocolException e) {

                } catch (IOException e) {
                    return new String("Exception: " + e.getMessage());


                }
                return "Data Submit Successfully";
            }

            @Override
            protected void onPostExecute(String result) {
                super.onPostExecute(result);

                Toast.makeText(getActivity(), "Data Submitted Successfully.", Toast.LENGTH_LONG).show();

            }
        }
        SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
        sendPostReqAsyncTask.execute(name, email, contact);
    }


}

无法使用php从表单中设置cookie

2 个答案: