Question

在这个数组集合中，我想只过滤那些到期的数组元素。如何在数组集合上使用过滤器查询？

  0 => array:7 [
    "semester" => "1"
    "fee_head" => "4"
    "fee_due_date" => "2018-04-07 00:00:00"
    "fee_amount" => 18000
    "discount" => 0
    "fine" => 0
    "paid_amount" => 1200
  ]
  1 => array:7 [
    "semester" => "1"
    "fee_head" => "4"
    "fee_due_date" => "2018-04-07 00:00:00"
    "fee_amount" => 18000
    "discount" => 0
    "fine" => 0
    "paid_amount" => 18000
  ]

计算到期日期： $ due =（fee_amount - （折扣+ paid_amount））+罚款如果（$由于大于0）那么我想得到以下输出

0 => array:7 [
            "semester" => "1"
            "fee_head" => "4"
            "fee_due_date" => "2018-04-07 00:00:00"
            "fee_amount" => 1800
            "discount" => 0
            "fine" => 0
            "paid_amount" => 1200
             "due"  => 600
      ]

Answer 1

使用Map类的Filter和Collections函数。你可以试试这个：

    $filtered = collect($your_original_array)->map(function ($item) {
                // Creating the 'due' key
                $item['due'] = ($item['fee_amount'] - ($item['discount'] + $item['paid_amount'])) + $item['fine'];
                return $item;

            })->filter(function ($item) {
                return $item['due'] > 0;
            });

    return $filtered;

PD：还没有测试过（这应该适用）但是你明白了。

Answer 2

您可以在获得该集合之前在查询中管理它。

YourModel::where('semester',1) // (other  filters)
        ->select(DB::raw('
            semester, fee_head, fee_due_date
            SUM(fee_amount) as  fee_amount,
            SUM(discount) as discount,
            SUM(fine) as fine,
            SUM(paid_amount) as paid_amount,
            (SUM(fee_amount) - (SUM(discount) + SUM(paid_amount)) + SUM(fine)) as due

        '))
        ->groupBy('semester') //
        ->get();

此答案是您查询的另一种方式

laravel

2 个答案: