Question

我想知道是否有人可以伸出援助之手指出我在这里做错了什么。我的任务是：

编写一个读取整数的程序，直到输入0。输入终止后，程序应报告输入的偶数整数（不包括0）的总数偶数整数的平均值，输入的奇数整数的总数，以及奇数整数的平均值

我设法做了类似的任务，但是有了字符（停在'＃'而不是0），我没有遇到问题。我在这里看不到或遗失的是什么？

#include <stdio.h>

int evenQ = 0, oddQ = 0, evenSum = 0, oddSum = 0; /* We initate variables */
int ch;

int main(void)
{
    while ((ch = getchar()) != 0 ) /* As long as the input is not 0 keep taking input*/
    {
        if (ch % 2 == 0) /* If the input is an even integer */
        {
            evenQ++; /* Add 1 to evenQ */
            evenSum += ch; /*Add the inputted int to evenSum */
        }
        else
        {
            oddQ++; /* Add 1 to oddQ */
            oddSum += ch; /* Add the inputted int to oddSum */
        }
    }

    printf("Total even integers:\t%d\n"
            "Total odd integers:\t%d\n"
            "Average even ints:\t%d\n"
            "Average odd ints:\t%d\n", evenQ, oddQ, (evenSum/evenQ), (oddSum/oddQ)); /* Print back
            the evenQ, oddQ and the averages of even integers and odd integers
            */

    return 0;
}

Answer 1

你的问题归结为getchar只能获取字符，而不是整数（如果输入1，则getchar将获取'1'-char，而不是int-）。使用scanf代替getchar，例如：

#include <stdio.h>

int evenQ = 0, oddQ = 0, evenSum = 0, oddSum = 0; /* We initate variables */
int ch;

int main(void)
{
    while ((scanf("%i", &ch) == 1) && (ch != 0 )) /* As long as the input is not 0 keep taking input*/
    {
        if (ch % 2 == 0) /* If the input is an even integer */
        {
            evenQ++; /* Add 1 to evenQ */
            evenSum += ch; /*Add the inputted int to evenSum */
        }
        else
        {
            oddQ++; /* Add 1 to oddQ */
            oddSum += ch; /* Add the inputted int to oddSum */
        }
    }

    printf("Total even integers:\t%d\n"
            "Total odd integers:\t%d\n"
            "Average even ints:\t%d\n"
            "Average odd ints:\t%d\n", evenQ, oddQ, (evenSum/evenQ), (oddSum/oddQ)); /* Print back
            the evenQ, oddQ and the averages of even integers and odd integers
            */

    return 0;
}

其他例子（最糟糕的方式，但更直观）：

#include <stdio.h>

int evenQ = 0, oddQ = 0, evenSum = 0, oddSum = 0; /* We initate variables */
int ch = -1;

int main(void)
{
    while (ch != 0 ) /* As long as the input is not 0 keep taking input*/
    {
        scanf("%i", &ch);

        if (ch != 0) // Do not take in care int 0
        {
            if (ch % 2 == 0) /* If the input is an even integer */
            {
                evenQ++; /* Add 1 to evenQ */
                evenSum += ch; /*Add the inputted int to evenSum */
            }
            else
            {
                oddQ++; /* Add 1 to oddQ */
                oddSum += ch; /* Add the inputted int to oddSum */
            }
        }
    }

    printf("Total even integers:\t%d\n"
            "Total odd integers:\t%d\n"
            "Average even ints:\t%d\n"
            "Average odd ints:\t%d\n", evenQ, oddQ, (evenSum/evenQ), (oddSum/oddQ)); /* Print back
            the evenQ, oddQ and the averages of even integers and odd integers
            */

    return 0;
}

我的程序没有正确读取整数。为什么？

1 个答案: