我对node.js
和Promise
功能都不熟悉,如果这个问题真的很愚蠢,请原谅我。
我正在尝试在Parent调用中创建一个子Promise
调用forEach
子项(如果这有意义的话)。
这是我的代码:
return new Promise(function(resolve, reject) {
var authorMapArray = new Array
db.sequelize.query(authorQuery, {
replacements: queryParams
}).spread(function(authorSitemap) {
authorSitemap.forEach(function(obj) {
/*
return new Promise (function(resolve, reject){
var thisQuery = photoQuery + ' AND author = ' + obj.id.toString();
db.sequelize.query(thisQuery, {
queryParams
}).spread(function(authorImages) {
var authorImageArray = new Array;
authorImages.forEach(function(obj) {
var imgLink = { url: imgHost + obj.img_id + '.jpg', title : img_tags }
authorImageArray.push(imgLink);
})
});
resolve(authorImageArray);
});
*/
var authorLink = { url: 'author/' + obj.id, /*img: authorImageArray,*/ changefreq: 'weekly', priority: 0.6, lastmodrealtime: true }
siteMapArray.push(authorLink);
});
resolve(siteMapArray);
//and finally create it
createSiteMap(siteMapArray);
});
})
你会注意到,中间的部分被注释掉了。当我运行这样的代码时,我得到了我期望的结果,即authorLink添加到站点地图中。当我取消注释代码时(为了在站点地图中包含与作者相关联的图像),甚至不添加作者链接。
如何将作者的图像包含在他们的记录中?
修改
这是更完整的代码:
function createSiteMap(myURLs) {
var rows = 10000;
var totalMaps = Math.trunc(myURLs.length/rows)+1;
var today = new Date();
var mySitemaps = new Array;
for (var i=1; i<totalMaps+1; i++) {
var filename = "public/sitemap-" + i.toString() + ".xml";
var sitemap = sm.createSitemap({
hostname: hostname,
cacheTime: 600000, //600 sec (10 min) cache purge period
urls: myURLs.slice((i-1)*rows,i*rows)
});
fs.writeFileSync(filename, sitemap.toString());
mySitemaps.push(filename);
}
// this needs to create sitemap tags not url tags
var smi = sm.buildSitemapIndex({
urls: mySitemaps
});
fs.writeFileSync("public/sitemap.xml", smi.toString());
process.exit();
}
function uniq(a) {
var seen = {};
return a.filter(function(item) {
return seen.hasOwnProperty(item) ? false : (seen[item] = true);
});
}
function getPhotos() {
return new Promise(function(resolve, reject) {
var siteMapArray = new Array()
var tags = new Array()
siteMapArray.push ({ url: '/' , changefreq: 'weekly', priority: 0.8, lastmodrealtime: true, lastmodfile: 'views/home.hbs' },)
db.sequelize.query(photoQuery, {
replacements: queryParams
}).spread(function(makeSiteMap) {
makeSiteMap.forEach(function(obj) {
// images for sitemap
var img_tags = obj.tags.replace(/,/g , " ");
var imgLink = { url: imgHost + obj.img_id + '.jpg', title : img_tags }
var siteLink = { url: 'photo/' + obj.img_id, img: imgLink, changefreq: 'weekly', priority: 0.6, lastmodrealtime: true }
siteMapArray.push(siteLink);
obj.tags = obj.tags.split(',').map(function(e) {
return e.trim().split(' ').join('+');
});
for (var tag in obj.tags) {
tags.push(obj.tags[tag])
}
});
resolve (siteMapArray);
//tags for sitemap
var uniqueTags = uniq(tags);
for (var tag in uniqueTags) {
var siteLink = { url: '/search/' + uniqueTags[tag], changefreq: 'weekly', priority: 0.8, lastmodrealtime: true }
siteMapArray.push (siteLink);
}
//now author tags
return new Promise(function(resolve, reject) {
var authorMapArray = new Array
db.sequelize.query(authorQuery, {
replacements: queryParams
}).spread(function(authorSitemap) {
authorSitemap.forEach(function(obj) {
/*
return new Promise (function(resolve, reject){
var thisQuery = photoQuery + ' AND author = ' + obj.id.toString();
db.sequelize.query(thisQuery, {
queryParams
}).spread(function(authorImages) {
var authorImageArray = new Array;
authorImages.forEach(function(obj) {
var imgLink = { url: imgHost + obj.img_id + '.jpg', title : img_tags }
authorImageArray.push(imgLink);
})
});
resolve(authorImageArray);
});
*/
var authorLink = { url: 'author/' + obj.id, /*img: authorImageArray,*/ changefreq: 'weekly', priority: 0.6, lastmodrealtime: true }
siteMapArray.push(authorLink);
});
resolve(siteMapArray);
//and finally create it
createSiteMap(siteMapArray);
});
})
});
});
};
getPhotos();
答案 0 :(得分:3)
好的,我们假设你想要这样的东西:
function getSiteMapArray() {
// return a promise that resolves to the siteMapArray
}
第一步是在不使用new Promise()
的情况下重写它 - 你不应该经常使用这个,因为大多数使用promises的工作只是链接.then()
调用,这些调用更具可读性。
请注意,.spread()
只是一个带有糖的.then()
。糖不是标准的Promise
语法,而是来自bluebird
sequelize
建议使用的插件。对于使用带有2个值的数组解析的promise,它们是等效的:
something.then(resultArray => ...);
something.spread((resultItem1, resultItem2) => ...);
(我将使用arrow functions,是吗?)
所以第一步是在我们开始合并您的评论中的代码之前,按照承诺摆脱new Promise()
:
function getSiteMapArray() {
var authorMapArray = new Array();
return db.sequelize
.query(authorQuery, {
replacements: queryParams
})
.spread(authorSitemap => {
authorSitemap.forEach(function(obj) {
var authorLink = {
url: "author/" + obj.id,
/*img: authorImageArray,*/
changefreq: "weekly",
priority: 0.6,
lastmodrealtime: true
};
siteMapArray.push(authorLink);
});
return siteMapArray;
});
}
够简单吗?
.query()
来获得结果承诺,.then()
或.spread()
传递处理结果的回调,spread()
会返回一个新的承诺,在我们完成所有操作后会解决,而此承诺是getSiteMapArray()
的结果。它将使用return siteMapArray
。我们可以使用map()
而不是forEach
进一步简化,只要您想要转换数组中的每个元素,建议使用function getSiteMapArray() {
return db.sequelize
.query(authorQuery, {
replacements: queryParams
})
.spread(authorSitemap => {
return authorSitemap.map(obj => ({
url: "author/" + obj.id,
/*img: authorImageArray,*/
changefreq: "weekly",
priority: 0.6,
lastmodrealtime: true
}));
});
}
:
function getSiteMapArray() {
return db.sequelize
.query(authorQuery, {
replacements: queryParams
})
.spread(authorSitemap => {
return authorSitemap.map(getAuthorDescription);
});
}
function getAuthorDescription(obj) {
return {
url: "author/" + obj.id,
/*img: authorImageArray,*/
changefreq: "weekly",
priority: 0.6,
lastmodrealtime: true
};
}
这就是容易的部分,现在我们如何在这里合并authorImage查询?
让我先提取一个帮手:
getAuthorDescription
现在function getAuthorDescription(obj) {
var thisQuery = photoQuery + " AND author = " + obj.id.toString();
return db.sequelize
.query(thisQuery, {
queryParams
})
.spread(function(authorImages) {
var authorImageArray = new Array();
authorImages.forEach(function(obj) {
var imgLink = { url: imgHost + obj.img_id + ".jpg", title: img_tags };
authorImageArray.push(imgLink);
});
return {
url: "author/" + obj.id,
img: authorImageArray,
changefreq: "weekly",
priority: 0.6,
lastmodrealtime: true
};
});
}
是同步的,但我们希望它自己进行查询,所以让我们把它重写为异步,这样它也会返回一个承诺!
.map()
使用function getSiteMapArray() {
return db.sequelize
.query(authorQuery, {
replacements: queryParams
})
.spread(authorSitemap => {
return authorSitemap.map(getAuthorDescription); // !!!
});
}
的另一个好例子,但我会留给你一个。
返回原始代码:
getAuthorDescription
哇,现在我们遇到了麻烦 - getSiteMapArray
返回了一个承诺,所以我们用一个承诺列表来解析getAuthorDescription
,而不是值列表!
我们需要一种方法来等待从function getSiteMapArray() {
return db.sequelize
.query(authorQuery, {
replacements: queryParams
})
.spread(authorSitemap => {
return Promise.all(authorSitemap.map(getAuthorDescription));
});
}
返回的每个承诺完成,并获得所有这些承诺的收集结果数组。这种方式称为Promise.all
:
所以代码变成:
abstract class AbstractSuperClass {
protected Entity entity;
protected abstract Action action; // all subclasses must define this on their own
public AbstractSuperClass(Entity entity) {
this.entity = entity;
}
public void operate() {
this.action.doVoidMethod();
}
}
public class SubClass extends AbstractSuperClass {
public SubClass(Entity entity) {
super(entity);
this.action = new Action(); // I define the "abstract" property
// now I expect SubClass.operate() to do this.action.doVoidMethod();
}
}
请告诉我这是否有帮助!
答案 1 :(得分:2)
您的实施中存在几个问题。我建议不要将[].foreach
用于儿童承诺。为子承诺制作单独的方法,并使用promise.all为每个authorSitemap
调用它。
以下是更新的示例实现。
return new Promise(function(resolve, reject) {
var authorMapArray = new Array
db.sequelize.query(authorQuery, {
replacements: queryParams
}).spread(function(authorSitemap) {
return Promise.all(authorSitemap.map(GetAuthor))
.then(function(authorImageArray){
var authorLink = { url: 'author/' + obj.id, img: authorImageArray, changefreq: 'weekly', priority: 0.6, lastmodrealtime: true }
siteMapArray.push(authorLink);
createSiteMap(siteMapArray);
resolve(siteMapArray);
})
.catch(function(error){
reject(error);
})
});
})
function GetAuthor(obj) {
return new Promise(function(reject,resolve){
var thisQuery = photoQuery + ' AND author = ' + obj.id.toString();
db.sequelize.query(thisQuery, { queryParams})
.spread(function(authorImages) {
var authorImageArray = new Array;
authorImages.forEach(function(obj) {
var imgLink = { url: imgHost + obj.img_id + '.jpg', title : img_tags }
authorImageArray.push(imgLink);
})
resolve(authorImageArray);
});
})
}