我正在开发一个网站,要求我创建上传.csv文件的功能。 上传文件时,表示格式错误,并显示以下消息:
C:\ XAMPP \ TMP \ php9F4F.tmp
p / s:我已经将excel文件转换为.csv逗号分隔格式,并在上传时仍然出错。
我该怎么做才能解决错误,然后将csv文件上传到我的数据库?
stdreport.php://我在这里使用import.php中的相同代码将它与数据库连接
<?php
$SQLSELECT = "SELECT stdCard, stdName, stdProgram, stdCourseDesc, stdCampus
FROM student
ORDER BY stdID
LIMIT 0,20";
$result_set = mysql_query($SQLSELECT, $conn);
while($row = mysql_fetch_array($result_set))
{
?>
import.php
<?php
$conn=mysql_connect("localhost","root","") or die("Could not connect");
mysql_select_db("dashboard",$conn) or die("could not connect database");
if(isset($_POST["Import"])){
echo $filename=$_FILES["file"]["tmp_name"];
if($_FILES["file"]["size"] > 0) {
$file = fopen($filename, "r");
while (($emapData = fgetcsv($file, 10000, ",")) !== FALSE) {
//It wiil insert a row to our subject table from our csv file`
$sql = "INSERT into student
(`stdID`, `stdCard`, `stdName`,
`stdOfficialEmail`,`stdEmail`,
`stdContNum`,`stdCourseDesc`, `stdCampus`,
`accessDate`)
values('$emapData[1]','$emapData[2]','$emapData[3]',
'$emapData[4]','$emapData[5]',
'$emapData[6]', '$emapData[7]','$emapData[8]',
'$emapData[9]')";
//we are using mysql_query function. it returns a resource on true else False on error
$result = mysql_query( $sql, $conn );
if(! $result ) {
echo "<script type=\"text/javascript\">
alert(\"Invalid File:Please Upload CSV File.\");
window.location = \"stdreport.php\"
</script>";
}
}
fclose($file);
//throws a message if data successfully imported to mysql database from excel file
echo "<script type=\"text/javascript\">
alert(\"CSV File has been successfully Imported.\");
window.location = \"stdreport.php\"
</script>";
//close of connection
mysql_close($conn);
}
}
?>