我正在尝试在我的数据库中插入一个普通的博客帖子,由于某种原因,它会插入两次相同的记录。我在下面给出了我的html和php代码。
<?php
if(isset($_POST["post"]))
{
$conn = new mysqli("localhost","root","","yomadsdata");
$post = $_POST["post"];
$heading = $_POST["heading"];
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO blogposts(blog_heading,blog_post) value
('$heading','$post')";
$result = $conn->query($sql);
if ($conn->query($sql) === TRUE)
{
echo "New post created successfully";
}
else
{
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
}
else
{
echo "Come in through proper ways.";
}
?>
答案 0 :(得分:1)
您执行两次查询$conn->query($sql)
。您可以在$result
if
$sql = "INSERT INTO blogposts(blog_heading,blog_post) value ('$heading','$post')";
if ($conn->query($sql) === TRUE) {
echo "New post created successfully";
}
或者你可以试试这个
if ($result) {
echo "New post created successfully";
}