Question

如何选择在03和04两个部门工作过的员工。在这个片段中，只有emp 0001和0004在03和04部门都有效。

id_employee  id_dept  workhours_percentage
-----------  -------  --------------------
0001           03         100
0001           04          50
0001           05          60
0002           05          60
0002           09          90
0002           08          80
0003           07          80
0003           06          60
0003           05          70
0004           03          75
0004           04          95
0004           02          25

Answer 1

试试这个：

SELECT id_employee 
FROM Your_Table
WHERE id_dept IN('03','04')
GROUP BY id_employee
HAVING COUNT(DISTINCT id_dept)=2

<强>输出：

id_employee
0001
0004

Answer 2

您可以使用GROUP_CONCAT功能和GROUP BY来实现此目的：

SELECT EMP_ID,
GROUP_CONCAT(DISTINCT DEPT ORDER BY DEPT ASC SEPARATOR '; ') DEPTS
FROM 
(
  SELECT '0001' EMP_ID, '03' DEPT, '100' WORK_PER FROM DUAL UNION ALL
  SELECT '0001' EMP_ID, '04' DEPT, '50' WORK_PER FROM DUAL UNION ALL
  SELECT '0001' EMP_ID, '05' DEPT, '60' WORK_PER FROM DUAL UNION ALL
  SELECT '0002' EMP_ID, '05' DEPT, '60' WORK_PER FROM DUAL UNION ALL
  SELECT '0002' EMP_ID, '09' DEPT, '90' WORK_PER FROM DUAL UNION ALL
  SELECT '0002' EMP_ID, '08' DEPT, '80' WORK_PER FROM DUAL UNION ALL
  SELECT '0003' EMP_ID, '07' DEPT, '80' WORK_PER FROM DUAL UNION ALL
  SELECT '0003' EMP_ID, '06' DEPT, '60' WORK_PER FROM DUAL UNION ALL
  SELECT '0003' EMP_ID, '05' DEPT, '70' WORK_PER FROM DUAL UNION ALL
  SELECT '0004' EMP_ID, '03' DEPT, '75' WORK_PER FROM DUAL UNION ALL
  SELECT '0004' EMP_ID, '04' DEPT, '95' WORK_PER FROM DUAL UNION ALL
  SELECT '0004' EMP_ID, '02' DEPT, '25' WORK_PER FROM DUAL
) EMP
GROUP BY EMP_ID
HAVING DEPTS LIKE '%03; 04%';

类似于Oracle的LISTAGG函数，它按照上述顺序聚合所述列值，并使用分隔符，在这种情况下为'; '。我们正在汇总DEPT列并使用EMP_ID对其进行分组，最后检查汇总列是否将所需的两个部门分隔为'; '。

希望这有助于解释。：）

如何找到在特定部门工作的员工

2 个答案: