如何实现app通信端口

Question

将以下代码保存为application.py可让我运行一个启动过程，显示一个带QDialog的简单QLabel：

python application.py

当进程正在运行并显示对话框时，我想更改默认标题＆＃34;在彩虹的某个地方＆＃34;别的东西。如何实现呢？

from PyQt5.QtGui import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
app = QApplication([])

class Dialog(QDialog):
    def __init__(self, parent=None):
        super(Dialog, self).__init__(parent)
        self.setLayout(QVBoxLayout())
        self.label = QLabel('somewhere over the rainbow')
        self.layout().addWidget(self.label)
        self.show()

dialog = Dialog()
app.exec_()

编辑：

以下是将QLabel的文字设置为新字符串值的示例＆＃34; 01011001001001110100100110＆＃34;：

Answer 1

以下是围绕SocketServer的{​​{1}}和TPCServer类设计的有效解决方案。

此实施使用BaseRequestHandler类。

QThread

application.py

import SocketServer from PyQt5.QtGui import * from PyQt5.QtWidgets import * from PyQt5.QtCore import * IP, PORT = '127.0.0.1', 62236 app = QApplication([]) class Emitter(QObject): signal = pyqtSignal(str) class Handler(SocketServer.BaseRequestHandler): emitter = Emitter() def handle(self): self.emitter.signal.emit(self.request.recv(1024)) class Thread(QThread): def __init__(self, target, parent=None): QThread.__init__(self, parent) self.target = target def run(self): while True: self.target() class Dialog(QDialog): def __init__(self, parent=None): super(Dialog, self).__init__(parent) Handler.emitter.signal.connect(self.onEmit) self.server = SocketServer.TCPServer((IP, PORT), Handler) thread = Thread(target=self.server.handle_request) thread.start() self.setLayout(QVBoxLayout()) self.label = QLabel('somewhere over the rainbow') self.layout().addWidget(self.label) self.show() def closeEvent(self, event): self.server.server_close() event.accept() def onEmit(self, arg): self.label.setText(str(arg)) dialog = Dialog() app.exec_()

client.py

使用import socket IP, PORT = '127.0.0.1', 62236 def send(data): SOCKET = socket.socket(socket.AF_INET, socket.SOCK_STREAM) SOCKET.connect((IP, PORT)) SOCKET.send(data) SOCKET.close() for i in range(2, 1000): send('data %07d'%i) send(raw_input("input:\t")) 使用threading.Thread方法代替SocketServer.TCPServer.serve_forever：

SocketServer.TCPServer.handle_request