使用“while”函数时，Python程序会一直崩溃

Question

编辑：

import random  # needed to generate random numbers

def roll_until_doubles():
    die_one = random.randrange(1, 7)
    die_two = random.randrange(1, 7)
    counter = 0
    while die_one != die_two:
        die_one = random.randrange(1, 7)
        die_two = random.randrange(1, 7)
        counter+=1
    return counter


def main():
    counter = roll_until_doubles()
    number_of_games = int(input("How many games would you like to play? "))
    for i in range(number_of_games):
        roll_until_doubles()
    print "Congratulations!"
    print "It took you " + str(counter) + " many rolls to roll doubles!"


main()

谢谢！它不再崩溃了。但是，我仍然在努力弄清楚如何打印骰子的价值。输出应该是例如：

dice 1 = 5 and dice 2 = 6
dice 1 = 4 and dice 2 = 8 
Congratulations!
It took you 2 rolls to roll doubles!

但我得到了这个：

Congratulations!
It took you [x] rolls to roll doubles!

如何打印骰子值？