Question

我正在尝试编写一个查询，该查询返回订单从开始到完成所用的时间。

我的表格如下所示。

Order No.   Action      DateTime
111         Start       3/23/2018 8:18
111         Complete    3/23/2018 9:18
112         Start       3/24/2018 6:00
112         Complete    3/24/2018 11:10

现在我正在尝试计算多个订单的开始和完成之间的日期差异，以下是我的查询：

Declare @StartDate VARCHAR(100), @EndDate VARCHAR(100), @Operation VARCHAR(100)

declare @ORDERTable table
(
    order varchar(1000)
)

insert into @ORDERTable values ('111')
insert into @ORDERTable values ('112')

Select @Operation='Boiling'

set @EndDate = (SELECT DATE_TIME from PROCESS WHERE ACTION='COMPLETE' AND ORDER in (select order from @ORDERTable) AND OPERATION=@Operation)

---SELECT @EndDate

set @StartDate = (SELECT DATE_TIME from PROCESS WHERE ACTION='START' AND ORDER in (select order from @ORDERTable) AND OPERATION=@Operation)

---SELECT @StartDate

SELECT DATEDIFF(minute, @StartDate, @EndDate) AS Transaction_Time

所以，我可以输入多个订单，但我也希望获得多个输出。

我的第二个问题是，如果我能够获得多个记录作为输出，我将如何确定哪个约会是哪个订单？

等待你的回答。提前谢谢。

我正在使用MSSQL。

Answer 1

您可以将表格拆分为两个临时表，cte，等等，然后将它们连接在一起以查找完成所需的时间

DECLARE @table1 TABLE (OrderNO INT, Action VARCHAR(100), datetime datetime)

INSERT INTO @table1 (OrderNO, Action, datetime)
VALUES 

(111         ,'Start'       ,'3/23/2018 8:18'),
(111         ,'Complete'    ,'3/23/2018 9:18'),
(112         ,'Start'       ,'3/24/2018 6:00'),
(112         ,'Complete'    ,'3/24/2018 11:10')



;with cte_start AS (
SELECT orderno, Action, datetime

FROM @table1
WHERE Action = 'Start')
, cte_complete AS (
SELECT orderno, Action, datetime

FROM @table1
WHERE Action = 'Complete')

SELECT 
start.OrderNO, DATEDIFF(minute, start.datetime, complete.datetime) AS duration

FROM cte_start start

INNER JOIN cte_complete complete
    ON start.OrderNO = complete.OrderNO

Answer 2

您可以按订单号进行汇总，并使用MAX或MIN与CASE WHEN进行汇总，以获取开始或结束时间：

select
  order_no,
  max(case when action = 'Start' then date_time end) as start_time,
  max(case when action = 'Completed' then date_time end) as end_time,
  datediff(
    minute, 
    max(case when action = 'Start' then date_time end), 
    max(case when action = 'Completed' then date_time end)
  ) as transaction_time
from process
group by order_no
order by order_no;

Answer 3

为什么不尝试使用基于集合的解决方案来解决此问题？毕竟，这就是RDBMS的用途。假设您在表格变量（{1}}中拥有您感兴趣的订单，它将符合以下内容：

@ORDERTable(Order)

如果SELECT DISTINCT [Order No.] , DATEDIFF( minute, FIRST_VALUE([DateTime]) OVER (PARTITION BY [Order No.] ORDER BY [DateTime] ASC), FIRST_VALUE([DateTime]) OVER (PARTITION BY [Order No.] ORDER BY [DateTime] DESC) ) AS Transaction_Time FROM tableName WHERE [Order No.] IN (SELECT Order FROM @ORDERTable);属性中的所有值都是开始或完成，但是如果它们之间还有其他值，则此查询有效。

详细了解Action窗口函数check out the documentation。

注意：适用于SQL Server 2012或更高版本。

SQL Query返回多个值

3 个答案: