Question

以下是AWS控制台中的所有内容。我的lambda函数定义了deletePost

case "deletePost":
   var id = event.arguments.id;
   callback(null, {id:-1,author:"me",title:"title"}); //note, regardless of what your args are right now it is returning id:-1
   break;

我的架构是

type Mutation {
   ...
   deletePost(id: ID!): Post!
}
type Post {
   id: ID!
   author: String!
   title: String
}

我的graphiQL查询

mutation DeletePost{
 deletePost(id: 3){
  id
 }  
}

出于某种原因，当我将id硬编码为-1时，它只是鹦鹉id=3回到我身边？如果我要求作者或头衔在我的查询中返回，我根本不会让他们回来。

更新完整的羊羔fxn。只是随aws appSync文档提供的模板的略微修改版本。

exports.handler = (event, context, callback) => {
console.log("Received event {}", JSON.stringify(event, 3));
var posts = { //in memory array store (simulates DB)
    "1": {"id": "1", "title": "First book", "author": "Author1"},
    "2": {"id": "2", "title": "Second book", "author": "Author2"},
    "3": {"id": "3", "title": "Third book", "author": "Author3"},
    "4": {"id": "4", "title": "Fourth book", "author": "Author4"},
    "5": {"id": "5", "title": "Fifth book", "author": "Author5"} };

console.log("Got an Invoke Request: "+event.field);
switch(event.field) {
    case "getPost":
        var id = event.arguments.id;
        callback(null, posts[id]);
        break;
    case "updatePost":
        posts[event.arguments.id]=event.arguments;
        console.log(posts);
        callback(null, event.arguments);
        break;
    case "deletePost":
        var id = event.arguments.id;
        //delete posts[event.arguments.id];
        callback(null, {id:-1,author:"me",title:"tits"});
        break;
    case "allPosts":
        var values = [];
        for(var d in posts){
            values.push(posts[d]);
        }
        callback(null, values);
        break;
    case "addPost":
        var id = event.arguments.id;
        posts[id]=event.arguments;
        console.log(posts);
        callback(null, event.arguments);
        break;
    case "addPostErrorWithData":
        var id = event.arguments.id;
        var result = posts[id];
        // attached additional error information to the post
        result.errorMessage = 'Error with the mutation, data has changed';
        result.errorType = 'MUTATION_ERROR';
        callback(null, result);
        break;
    default:
        callback("Unknown field, unable to resolve" + event.field, null);
        break;
  }
};

解析器。在大多数情况下，只需直接传递数据。

#request mapping
{
    "version" : "2017-02-28",
    "operation": "Invoke",
    "payload": {
        "field": "addPost",
        "arguments":  $util.toJson($context.arguments)
    }
}
#responce mapping
$util.toJson($context.result)

Answer 1

如果没有看到所有Lambda函数以及解析器模板，很难知道。从上面的代码我猜你以本教程为出发点：https://docs.aws.amazon.com/appsync/latest/devguide/tutorial-lambda-resolvers.html

假设您将结果传回响应模板，例如$util.toJson($context.result)，那么问题很可能与您的Lambda函数中的回调结构有关

let result = {"id" :-1, "author":"me", "title":"title"}
callback(null, result);

基本上，您需要传回一个结果对象，以便在$context对象中看到它，并将其转换为对调用者的GraphQL JSON响应。

具有Lambd函数后端的AWS appsync，GraphQL为Query提供了意外的repsonce

1 个答案: