Question

我有2个班级，一个用于用户详细信息，另一个用于用户健身我想要的是使用 FitnessRecordRepository.findAll（）从FitnessRecord类的最终json对象中排除 name 字段。这是我现在的json输出。

{
    "fitness_id": 1,
    "date_of_performance": "2018-04-06",
    "user": {
        "user_id": 1,
        "name": "Hilal Kaldane",
        "email": "hilalkaldane@gmail.com"
    }
}

我想要的是

{
    "fitness_id": 1,
    "date_of_performance": "2018-04-06",
    "user": {
        "user_id": 1,
        "email": "hilalkaldane@gmail.com"
    }
}

User.class

public class User {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer user_id;

@NotNull
private String name;

@NotNull
@Column(unique = true)
private String email;

@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "user")
private Set<FitnessRecord> fitness_record = new HashSet<>();



//Getter and Setters are omitted
}

FitnessRecord.class

public class FitnessRecord {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer fitness_id;

public Integer getFitness_id() {
    return fitness_id;
}

public void setFitness_id(Integer fitness_id) {
    this.fitness_id = fitness_id;
}

@JoinColumn(name="user_id")
@ManyToOne
private User user;

@Temporal(TemporalType.DATE)
private Date date_of_performance;
}

注意： - 我不想在用户类上使用JSON忽略，因为我将使用 名称 字段其他地方，如用户信息检索

在springboot中序列化一对多关系时，防止排除JSON对象的字段

0 个答案: