Question

我想从这个HTML代码中获取一些具体信息：

<div class="main">    
    <div class="a"><div><a>linkname1</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="b">xxx</div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname2</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname3</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname4</a></div></div> <!-- I want get the text of this 'a' tag -->  
    <div class="a"><div><a>linkname5</a></div></div> <!-- I want get the text of this 'a' tag --> 
    <div class="d"></div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname6</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname7</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname8</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="d"></div>
    <div class="c">xxx</div>
    <div class="a"><div><a>linkname9</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
    <div class="a"><div><a>linkname10</a></div></div> <!-- I DON'T want get the text of this 'a' tag --> 
</div>

我想在数组中获取'second''a'（class）标记块中链接文本的列表（在第一个div与类'c'之间，第二个div在类'c'之间）。我怎么能通过xpath选择器做到这一点？可能吗？我找不到怎么做..

以我的例子为例，预期的结果是：

linkname2
linkname3
linkname4
linkname5

谢谢:)

Answer 1

您的问题是 Set 问题，如本答案中所述：[{3}}。

因此，应用于您的特定情况，您应该使用交集，如下所示：

(: intersection :)
$set1[count(. | $set2) = count($set2)]

set1 应该是div[@class='c']和
之后的跟随集 set2 应该是div[@class='d']之前的前一组。

现在，按照上面的公式将两者放在一起

set1 = "div[@class='c'][1]/following-sibling::*" and
set2 = "div[@class='d'][1]/preceding-sibling::*"

XPath表达式可能如下所示：

div[@class='c'][1]/following-sibling::*[count(. | current()/div[@class='d'][1]/preceding-sibling::*) = count(current()/div[@class='d'][1]/preceding-sibling::*)]

输出

linkname2
linkname3
linkname4
linkname5

Answer 2

你可以尝试这个表达式：

/div/div[position() > 3 and position() < 8]/div/a/text()

Answer 3

我找到了一个可能的解决方案:)

//following::div[@class='a' and count(preceding::div[@class="c"]) = 1]/div/a/text()

通过xpath选择器从html标签的liste中选择特定的html标签

3 个答案: