Question

假设我有一个像这样的文件夹结构：

根
- Folder1中
  - 文件夹4
- FOLDER2
  - Folder3
    - Folder5
- 文件夹6

我有一个包含所有路径的数组：

let paths = ['/root/','/root/folder1/','/root/folder2','/root/folder2/folder3'...

我想要完成的是删除递归子项的父目录，以便我最终得到这个：

let paths = ['/root/folder1/folder4','/root/folder2/folder3/folder5','/root/folder6'];

不要担心这不是家庭作业或任何事情，只是我被困在我的个人项目上：D
如果您可以使用伪代码（甚至更好的JavaScript）来回答这很酷。

Answer 1

您可以检查数组是否包含以给定路径开头的字符串。然后过滤掉该项目。

＆＃13;

var paths = ['/root/', '/root/folder1/', '/root/folder2', '/root/folder2/folder3/', '/root/folder1/folder4', '/root/folder2/folder3/folder5'],
    result = paths.filter((p, i, a) => !a.slice(i + 1).some(o => o.startsWith(p)));
    
console.log(result);

＆＃13;

Answer 2

我使用filter＆amp;以不同方式尝试了它而是some API

    let paths = ['/root/', '/root/folder1/', '/root/folder1/folder4/', '/root/folder2', '/root/folder2/folder3', , '/root/folder2/folder3/folder5', , '/root/folder6/'];

console.log(paths.filter((path) => {
        return !paths.some((indexPath) => { return path !== indexPath && indexPath.indexOf(path) > -1 });
}));

从数组中删除父目录

2 个答案: