Question

我有这个代码，我用来登录移动设备用户，并且这样做我正在检查一些用户输入，并希望查询表是否存在字符串。我希望getSingleResult()出现问题，但getResultList出现问题。

这是代码

//Mobile Login
        @ResponseBody
        @RequestMapping(value = { "/mobileloginbackend" }, method = RequestMethod.POST)
        public String mobilelogin(@RequestParam String ssoId,@RequestParam String password) {

        Session currentSession = sessionFactory.getCurrentSession();
        @SuppressWarnings("rawtypes")
        Query theQuery = currentSession.createSQLQuery("select password from accounts where sso_id=:name");
        theQuery.setParameter("name", ssoId);
        List list = theQuery.getResultList();
        String stored_password = list.get(0).toString();

        if(list.isEmpty()){
            return "that user does not exist";
        }

        if(list.size() == 0){
        return "that user does not exist";  
        }

        if(passwordEncoder.matches(password,stored_password)){
            return "successful login";
        }
        else{
            return "wrong credentials";
        }

        }

这两行是提供异常的行

if(list.isEmpty()){
            return "that user does not exist";
        }

        if(list.size() == 0){
        return "that user does not exist";  
        }

我收到错误500（内部服务器错误）。

我怎样才能做到这一点？。

Answer 1

如果你的名单确实是空的，你是否从这一行得到ArrayIndexOutOfBoundsException：

String stored_password = list.get(0).toString();

在尝试获取第一个元素之前，您应首先检查它是否为空。

顺便说一下，if(list.isEmpty())和if(list.size() == 0)完全相同。

Answer 2

这最终对我有用

        //Mobile Login
        //import javax.persistence.NoResultException;
        @ResponseBody
        @RequestMapping(value = { "/mobileloginbackend" }, method = RequestMethod.POST)
        public String mobilelogin(@RequestParam String ssoId,@RequestParam String password) {

        try {
        Session currentSession = sessionFactory.getCurrentSession();
        @SuppressWarnings("rawtypes")
        Query theQuery = currentSession.createSQLQuery("select password from accounts where sso_id=:name");
        theQuery.setParameter("name", ssoId);
        String stored_password = theQuery.getSingleResult().toString();
        if(passwordEncoder.matches(password,stored_password)){
            return "successful login";
        }
        else{
            return "wrong credentials";
        }
          }
       catch (NoResultException e) { 
         return "That user does not exist.";
         }

        }

使用createSQLQuery时，Spring getSingleResult（）和getResultList（）异常

2 个答案: