Question

我试图获取特定字符串的引号之间的值例如，对于'IsEmployee＆＃39;关键，我需要得到价值＆＃39;是＆＃39;

ID：＆＃39; 1234＆＃39;，薪酬：＆＃39; 200000＆＃39;，年份：＆＃39; 2018＆＃39;，IsEmployee：＆＃39;是＆＃39;
任何人都可以分享任何样本正则表达式

Answer 1

它似乎是JSON格式，虽然是一个字符串。请使用JSON解析器以更灵活地通过键获取任何值，或者打印所有

Answer 2

试试这个

import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class RegexpApp {

    public static void main(String[] args){
        String val = "id:'1234',Salary:'200000',Year:'2018',IsEmployee:'Yes'";
        System.out.println(getValue(val, "id"));
        System.out.println(getValue(val, "Year"));
        System.out.println(getValue(val, "IsEmployee"));

    }

    public static String getValue(String testStr, String key){
        Pattern p = Pattern.compile("\\b"+key+"[ ]*:[ ]*'(.+?)'");
        Matcher m = p.matcher(testStr);
        return  m.find() ? m.group(1): null;
    }
}

Answer 3

您可以使用以下正则表达式：

(?i)(?<=isemployee:')[^']*

Click for Demo

<强>解释

(?i) - 使正则表达式不区分大小写
(?<=isemployee:') - 找到位置的正面观察，其前面是isemployee:'
[^']* - 匹配任何不是'的字符的0次出现。简而言之，它匹配所有内容，直到在字符串

'

代码：OUTPUT

import java.util.*;
import java.lang.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

class Rextester
{  
    public static void main(String args[])
    {
        final String regex = "(?i)(?<=isemployee:')[^']*";
        final String string = "id:'1234',Salary:'200000',Year:'2018',IsEmployee:'Yes'";

        final Pattern pattern = Pattern.compile(regex);
        final Matcher matcher = pattern.matcher(string);

        while (matcher.find()) {
            System.out.println("Full match: " + matcher.group(0));
            for (int i = 1; i <= matcher.groupCount(); i++) {
                System.out.println("Group " + i + ": " + matcher.group(i));
            }
        }
    }
}

Java - 正则表达式获取特定字符串后的值

3 个答案: