Question

我一直在练习让我对基础知识更加熟悉，但是这个程序不会按照我想要或期望它运行。我已经使用输入等编写了类似的代码但是第一次发生在我身上，所以我想知道为什么这段代码没有按预期工作。

我希望程序问我"Type '1' if you agree - Type '0' if you decline." 21次，并根据输入1 or 0，它会在变量协议或下降中添加一个，当然，在插入输入之后显示当前分数：

Who wants to play volleyball on sunday from 4pm to 6pm?
If more 12 or more people agree, I will book a field for us.
Type '1' if you agree - Type '0' if you decline.
1
1 YES vs. 0 NO
Type '1' if you agree - Type '0' if you decline.
0
1 YES vs. 1 NO
Type '1' if you agree - Type '0' if you decline.

# and so on...

但相反它给了我：

Who wants to play volleyball on sunday from 4pm to 6pm?
If more 12 or more people agree, I will book a field for us.
Type '1' if you agree - Type '0' if you decline.
1
11
11
1 YES vs. 0 NO
Type '1' if you agree - Type '0' if you decline.
0
00
1 YES vs. 1 NO
Type '1' if you agree - Type '0' if you decline.
0
00
1 YES vs. 2 NO
Type '1' if you agree - Type '0' if you decline.
0
00
1 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
11
2 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
11
3 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
11
4 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
11
5 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
11
6 YES vs. 3 NO
Type '1' if you agree - Type '0' if you decline.
1
10
6 YES vs. 4 NO
Type '1' if you agree - Type '0' if you decline.
0
01
7 YES vs. 4 NO
Type '1' if you agree - Type '0' if you decline.
0
00
7 YES vs. 5 NO
Type '1' if you agree - Type '0' if you decline.
1
11
8 YES vs. 5 NO
Type '1' if you agree - Type '0' if you decline.
1
11
9 YES vs. 5 NO
Type '1' if you agree - Type '0' if you decline.
1
11
10 YES vs. 5 NO
Type '1' if you agree - Type '0' if you decline.
1
10
10 YES vs. 6 NO
Type '1' if you agree - Type '0' if you decline.
1
10
10 YES vs. 7 NO
Type '1' if you agree - Type '0' if you decline.
0
00
10 YES vs. 8 NO
Type '1' if you agree - Type '0' if you decline.
0
01
11 YES vs. 8 NO
Type '1' if you agree - Type '0' if you decline.
1
11
12 YES vs. 8 NO
Type '1' if you agree - Type '0' if you decline.
1
11
13 YES vs. 8 NO
Type '1' if you agree - Type '0' if you decline.
1
Cool,I am gonna book a field for us.SEE YOU ON SUNDAY at 4pm.LET'S GOOOOO!!!
Have a nice week until then !

如果您想知道为什么有时会11, 00, 01 or 10：第二个数字是我必须再次作为输入插入的，第一个数字由程序打印。

如果只有一个号码1 or 0：这是我的意见。

正如您可能已经注意到的那样：我插入第一个或第二个作为输入并不重要。由于某种原因，只有最后一个输入很重要并且很重要，我不知道。

（我还没想出你的代码如何可视化（如：斜体，粗体或颜色），这就是为什么我必须在这里解释一下代码......）

我的代码：

print("Who wants to play volleyball on sunday from 4pm to 6pm?")
print("If more 12 or more people agree, I will book a field for us.")
print("Type '1' if you agree - Type '0' if you decline.")

answer = input()
z = int(input(answer))
agreements = 0
declines = 0

for i in range(0, 21):
    try:
        z = int(input(answer))
        if z == 1:
            agreements += 1
            print(agreements, "YES vs.", declines, "NO")
            print("Type '1' if you agree - Type '0' if you decline.")

            answer = input()
        elif z == 0:
            declines += 1
            print(agreements, "YES vs.", declines, "NO")
            print("Type '1' if you agree - Type '0' if you decline.")

            answer = input()
        else:
            raise
    except:
        print("Please type '1' or '0'.Try again.")

if agreements >= 12:
    print("Cool,I am gonna book a field for us."
          "SEE YOU ON SUNDAY at 4pm."
          "LET'S GOOOOO!!!")
else:
    print("Unfortunately we didn't manage to get enough people for booking a field."
          "Maybe next time! :)")

print("Have a nice week until then !")

无论我如何看待它，我都无法在这里找到问题。这将是一个如此愚蠢的错误...

我事先道歉并表示感谢。

Answer 1

你要求更多input()，那么你应该。代码中的每个input()都会打印括号中的内容（如果有的话）并等待用户输入：你。

这就是为什么你认为有更多的输入 - 你认为不应该发生很多输出。基本上你是在提示自己输入一些文本，然后将其用作信息并打印为代码中下一个输入（）的提示......

此：

answer = input()  # input-prompt. no output. will store inputted thing in answer
z = int(input(answer))  # input-prompt. Will print content of 'answer' as message
                        # and wait for another input of you
agreements = 0
declines = 0

# etc..... same for your inner loops.

下一个问题：即使输入的输入无效，你的for循环也会增加，所以如果错误输入了21次，你就不会被问到21次“有效”。

你可以简单地通过不使用“数字”来比较并使用函数来询问，只要给出无效输入：

def agreeToPlay():
    """Loop until either 0 or 1 is inputted - remove whitespsaces for convenience.
    Returns True on agreement, else False"""

    # loop with no end
    while True:
        choice = input("Type '1' if you agree - Type '0' if you decline:").strip()

        # only way out of the while is by inputing either 0 or 1:
        if choice in ["1","0"]:
            # only way to break out of the endless loop is valid input
            return choice == "1"  # return True if 1 else False

您在主程序中使用此功能：

print("Who wants to play volleyball on sunday from 4pm to 6pm?")
print("If more 12 or more people agree, I will book a field for us.")
print("Type '1' if you agree - Type '0' if you decline.")

agreements = 0
declines = 0
answers = []

# shortcut:
# while agreements + declines < 21 and agreements < 12  # ends as soon as 12 agreed

while agreements + declines < 21: 
    if agreeToPlay(): # ask until valid, then increment the correct one based
                      # on return of True / False
        agreements += 1
    else:
        declines +=1 

    print(agreements, "YES vs.", declines, "NO")

if agreements >= 12:
    print("Cool,I am gonna book a field for us."
          "SEE YOU ON SUNDAY at 4pm."
          "LET'S GOOOOO!!!")
else:
    print("Unfortunately we didn't manage to get enough people for booking a field."
          "Maybe next time! :)")

为什么程序在执行前会多次询问输入？

1 个答案: