Question

我在导航器中递归添加路线。可能有20个或更多视图。 Pop按宣传方式工作，但我想弹出索引1，并删除所有推送历史记录。有没有办法用像... returntoIndex0 ...

这样的东西替换这个pop命令

//========================================================
      new ListTile(
        title: new RaisedButton(
          child: new Text("POP"),
          onPressed: () {
            var route = new MaterialPageRoute(
              builder: (BuildContext context) =>
                  new NextPage3(value:"hi there from 3"),
            );
            Navigator.pop(context);
          },
        ),
      ),

// ============================================= ===========

Answer 1

如果您使用MaterialPageRoute创建路由，则可以使用以下命令：

Navigator.popUntil(context, ModalRoute.withName(Navigator.defaultRouteName))

Navigator.defaultRouteName反映了应用程序启动的路径。这是一段代码，更详细地说明了它：

child: InkWell(
          child: Row(
            mainAxisAlignment: MainAxisAlignment.spaceEvenly,
            children: <Widget>[
              Image(
                image: AssetImage('assets/img/ic_reset.png'),),
              Text('Change my surgery details',
                style: TextStyle(color: Colors.blue, decoration: TextDecoration.underline),),
            ],
          ),
          onTap: () =>
              Navigator.popUntil(context, ModalRoute.withName(Navigator.defaultRouteName))
        ),

希望这会有所帮助。

Answer 2

如果您不使用命名路由，则可以使用

Navigator.of(context).popUntil((route) => route.isFirst);

Answer 3

您也可以这样

Navigator.of(context)
            .pushNamedAndRemoveUntil('/Destination', ModalRoute.withName('/poptillhere'),arguments: if you have any);

用例是转到所需的屏幕，然后根据需要弹出它们之间的屏幕。

有关更多信息，您可以检查此Post Explaining other Solutions

Answer 4

使用文档中提到的popUntil方法

典型用法如下：

Navigator.popUntil(context, ModalRoute.withName('/login'));

Answer 5

如果您确切知道应该执行多少次弹出：

例如2次弹出：

count = 0;
Navigator.popUntil(context, (route) {
    return count++ == 2;
});

Answer 6

此处Dashboard（）是屏幕名称。因此，这将弹出所有屏幕并转到Dashboard（）屏幕。

const defVal: DefaultType = {...};
const inferedVal: AnyTypeOfChoice = {...};
const a = new A((defVal) => {...});
const a2 = new A((inferedVal) => {...}, async () => inferedVal);

Answer 7

对我来说，我在推送新页面时使用了它：

widget = MyWidget();
Route route = CupertinoPageRoute(builder: (context) => widget, settings:RouteSettings(name: widget.toStringShort()));
Navigator.push(context, route);

然后返回到特定页面：

Navigator.of(context).popUntil((route) => route.settings.name == "MyWidget");

Answer 8

我在本文中尝试了其他答案，并以某种方式导致以下异常。

To safely refer to a widget's ancestor in its dispose() method, save a reference to the ancestor by calling dependOnInheritedWidgetOfExactType() in the widget's didChangeDependencies() method.

The relevant error-causing widget was
    MaterialApp 
lib/main.dart:72
When the exception was thrown, this was the stack
#0      Element._debugCheckStateIsActiveForAncestorLookup.<anonymous closure> 
package:flutter/…/widgets/framework.dart:3781
#1      Element._debugCheckStateIsActiveForAncestorLookup 
package:flutter/…/widgets/framework.dart:3795
#2      Element.dependOnInheritedWidgetOfExactType 
package:flutter/…/widgets/framework.dart:3837
#3      Theme.of 
package:flutter/…/material/theme.dart:128
#4      XXxxXX.build.<anonymous closure> 
package:xxx/widgets/xxx.dart:33
...
════════════════════════════════════════════════════════════════════════════════

以下答案解决了该问题。 https://stackoverflow.com/a/52048127/2641128

Navigator.pushNamedAndRemoveUntil(context, '/', (_) => false);

Answer 9

这总是让我得到预期的结果。并且会弹出到当前导航栈的路由

 Navigator.of(context, rootNavigator: true).pop();

Answer 10

//========================================================
          new ListTile(
            title: new RaisedButton(
              child: new Text("POP until"),
              onPressed: () {
                var route = new MaterialPageRoute(
                  builder: (BuildContext context) =>
                      new NextPage3(value:"hi there from 3"),
                );
               //Navigator.pop(context, ModalRoute.withName('/'));
                Navigator.popUntil(context,ModalRoute.withName('/'));                
              },
            ),
          ),
//========================================================

用.popUntil替换.pop，实际上非常优雅。

Flutter Navigation弹出到索引1

10 个答案: