Question

我是一名初学者，致力于使用Python书籍自动化无聊的东西。我坚持这个练习题。说明如下：

幻想游戏库存的字典功能列表：

想象一下，被征服的龙的战利品被表示为一串字符串像这样：

dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']

编写一个名为addToInventory(inventory, addedItems)的函数，其中 inventory参数是表示玩家库存的字典（如在上一个项目中）addedItems参数是一个类似dragonLoot的列表。 addToInventory()函数应返回表示更新库存的字典。请注意，addedItems列表可以包含同一项的多个。您的代码可能如下所示：

def addToInventory(inventory, addedItems):


    inv = {'gold coin': 42, 'rope': 1}
    dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
    inv = addToInventory(inv, dragonLoot)
    displayInventory(inv)

上一个程序（使用displayInventory()函数以前的项目）将输出以下内容：

Inventory:
45 gold coin
1 rope
1 ruby
1 dagger
Total number of items: 48

我的代码如下

    def addtoinventory(inventory,lootlist):
    for i in range(len(lootlist)):
        if lootlist[i] in inventory:
            inventory[lootlist[i]] = inventory[lootlist[i]] + 1

    else:
        inventory.setdefault(lootlist[i],1)

        return inventory


def displayinventory(inventory):
    total_items = 0

    for k,v in inventory.items():
        print(k + ' : ' + str(v))

        total_items = total_items + v

    print("Total number of items: " + str(total_items))


    inv = {'gold coin': 42, 'rope': 1}
    dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
    inv = addtoinventory(inv, dragonLoot)
    displayinventory(inv)

我的输出是这样的：

gold coin : 45
ruby : 1
rope : 1
Total number of items: 47

我做错了什么？

Answer 1

我认为你的else:缩进是错误的。您应该使用if-else，但您的代码是for-else。下面的代码效果很好。

def addtoinventory(inventory,lootlist):
    for i in range(len(lootlist)):
        if lootlist[i] in inventory:
            inventory[lootlist[i]] = inventory[lootlist[i]] + 1
        else:
            inventory.setdefault(lootlist[i],1)
    return inventory

结果如下。

>>> inv = {'gold coin': 42, 'rope': 1}
>>> dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
>>> inv = addtoinventory(inv, dragonLoot)
>>> inv
{'gold coin': 45, 'rope': 1, 'dagger': 1, 'ruby': 1}

Answer 2

我复制了您的代码，对我来说很好用，除了项目及其编号的顺序错误之外，如果将打印行更改为此，则很容易解决：

print(str(v)+' : '+k)

Answer 3

这就是我解决的方法。但是我无法摆脱括号，由于某种原因，pprint无法正常工作。但这代码还是可以达到目的的...

inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']  

#Turn dragonLoot list in to a dictionary:
list={}
for i in dragonLoot:
    if i not in list:
        list.setdefault(i, 1)
    elif i in list:
        list[i] = list[i] +1

#Merge dictionaries:
for i, v in list.items():
    if i not in inv:
        inv.setdefault(i, 1)
    elif i in inv:
            inv[i]=inv[i]+v

import pprint

print('Inventory: ')
pprint.pprint(inv, width=1)
print('')
total=0

#Count the total number of items:
for i, v in inv.items():
    total=total+v

print('Total number of items: ' + str(total))

Answer 4

def displayInventory(inventory):
    print("Inventory:")
    item_total = 0
    for k, v in inventory.items():
        item_total += v
        print(str(v) + ' ' + str(k))
    print("Total number of items: " + str(item_total))

def addToInventory(inventory, addItems):
    for k in range(len(addItems)):
        inventory.setdefault(addItems[k], 0)
        inventory[addItems[k]] += 1
    return(inventory)

inventory = {'rope': 1, 'torches': 6, 'gold coins': 42, 'daggers': 28, 'arrows': 12, 'knives': 50}
dragonLoot = ['gold coins', 'daggers', 'gold coins', 'gold coins', 'ruby']
updatedInventory = addToInventory(inventory, dragonLoot)
displayInventory(updatedInventory)
print("Inventory updated.")

Answer 5

尝试以下操作：

def addToInventory(dragonLoot,inv):
    count={}
    for item in dragonLoot:
        count.setdefault(item,0)
        count[item]=count[item]+1

    for k in count.keys():
        if k in inv.keys():
            inv[k]=inv[k]+count[k]
    print(inv)

Answer 6

您正在字典中搜索范围，并且代码中出现意外缩进的问题

    playerInventory = {'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}
    dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']

    def addToInventory(inventory, addedItems):
        for i in addedItems:
            if i not in inventory:
                inventory.setdefault (str(i), 1)
            else:
                inventory[i] = inventory[i] + 1
        return inventory

    playerInventory = addToInventory(playerInventory, dragonLoot)
    print(playerInventory)

Answer 7

我刚进入书中，在这里我如何解决它，看起来很简单：

inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']


def addToInventory(backpack, added_items):
    for i in added_items:
        if i in backpack:
            backpack[i] += 1
        else:
            count = 0
            count += 1
            backpack[i] = count

    return backpack

Answer 8

inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
def addToInventory(inventory, addedItems):
        for i in range(len(addedItems)):
            if addedItems[i] in inventory:
                inventory[addedItems[i]] = inventory[addedItems[i]] + 1
            else:
                inventory.setdefault(addedItems[i],1)
        return inventory                
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)

Answer 9

这是我的解决方案：

# inventory.py
# stuff = {'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}
def displayInventory(inventory):
    print("Inventory:")
    item_total = 0
    for k, v in inventory.items():
        print(str(v) + ' ' + k)
        item_total += v
    
    print("Total number of items: " + str(item_total))

def addToInventory(inventory, addedItems):
    for i in addedItems:
        #copy() is for to avoid RuntimeError: dictionary changed size during iteration
        for k, v in inventory.copy().items():  
            if k == i:
                inventory[k] = v + 1
            if i not in inventory.keys():
                inventory[i] = 1
                    
    return inventory
inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = addToInventory(inv, dragonLoot)
displayInventory(inv)
# displayInventory(stuff)

Answer 10

我就是这么想的。想分享，因为这是我在没有帮助的情况下做的第一个。希望它有所帮助，欢迎所有反馈。

`

dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
inv = {'gold coin':42, 'rope': 1}

def addToInventory(inventory, addedItems):
    for loot in addedItems:
        inventory.setdefault(loot, 0)
        for k, v in inventory.items():
            if loot == k:
                inventory[loot] = v + 1

def displayInventory(inventory):
    totalItems = 0
    for k, v in inventory.items():
        print(str(v) + '---' + str(k))
        totalItems += v
    print('Total number of items: '+ str(totalItems))
  
addToInventory(inv, dragonLoot)  
displayInventory(inv)

`

Answer 11

我就是这样做的。我认为这是 addToInventory() 函数的一个干净的解决方案。你怎么认为？还是我错过了什么？

PlayerInventory = {"gold coin": 42, "rope": 1}
dragonLoot = ["gold coin", "dagger", "gold coin", "gold coin", "ruby"]


def displayInventory(inventory):  # Displays the Inventory
    print("Inventory:")
    cnt = 0
    for k, v in inventory.items():
        print(k + " : " + str(v))
        cnt += v
    print(f"Total number of items: {cnt}")


def addToInventory(inventory, addedItems):  # Add items to the provided inventory
    for item in addedItems:  # Loops trough the provided list.
        inventory.setdefault(item, 0)  # Checks if the key exists. If not, adds it with a value of 0.
        inventory[item] += 1  # Adds 1 to the value.
    return inventory  # returns the complete Dictionary


PlayerInventory = addToInventory(PlayerInventory, dragonLoot)
displayInventory(PlayerInventory)

Answer 12

def add(inventory,items):
    for j in items:

        for i ,k in inventory.copy().items():
            if i==j:
                inventory[i]=k+1
            else:
                inventory.setdefault(j,1)                   
    print(inventory)            

inv = {'gold coin': 42, 'rope': 1}
dragonLoot = ['gold coin', 'dagger', 'gold coin', 'gold coin', 'ruby']
add(inv,dragonLoot)

我认为这是最好的方法

Answer 13

items={'rope': 1, 'torch': 6, 'gold coin': 42, 'dagger': 1, 'arrow': 12}

def displayInventory(*inventory):
    total_items = 0
    for i, j in items.items():
        print(j, i)
        total_items += j
    print("Total number of items: " + str(total_items))

displayInventory()

幻想游戏库存的输出问题

13 个答案: